Can yall help me i have been sitting here for a 1 hour try to do this plz help
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Answer:
<em>They will catch up at 2.5 hours</em>
Step-by-step explanation:
Constant Speed Motion
It refers to situations where objects move at the same speed in the same direction. The speed is computed as the ratio of the distance x to the time
The situation pictured in the question requires the computation of distances traveled by two objects running at different speeds. The slower car goes ahead with a 35-mile head start, so it's just a matter of time when the fastest car and the slower will catch up. We'll use here the concept of relative speed to easily solve the problem.
The speed of the first friend is
And the speed of the second friend is
If the first friend was at rest, the second friend will have a relative speed of
The distance between them (35 miles) will be covered in a time t which can be found from
We need to check if they have not arrived to chincoteague by that time. We'll compute the distance of the fastest friend
We can see they catch up (200-162.5=37.6 miles) before arriving to their destiny.
Just to verify, the distance traveled by the first friend is
The difference of those distances is 162.5-127.5=35 miles, exactly the original head-start