Take half of the coefficient of x: It is 3, and half that is 3/2.
Then <span>x^2+3x=6 becomes:
</span><span> x^2+3x + (3/2)^2 =6 + (3/2)^2, and
(x+3/2)^2 = 6 + 9/4
You were not asked to solve the equation, but why not do it for the practice?
</span>Solve (x+3/2)^2 = 6 + 9/4 for x. There will be 2 values.
Answer: <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>
Step-by-step explanation:
The equation
can be solved by squaring both sides:

We can see that -1 and 7 are solutions, but make sure they are not extraneous by substituting them in the original equation:

The square root of 49 equals 7, but the square root of -1 is an imaginary number.
The correct choice is <em>"7 is a solution to the original equation. The value –1 is an extraneous solution."</em>
Fractions,rats, and percents all interconnect. For ext,50%=11/2 =1:2
I’m learning this right now actually! The first one is...pretend the 2 is small. x2+2-15 and the second answer is x2+7-30!