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irakobra [83]
3 years ago
15

Can we prove that △PQR and △PQS are congruent using the side-side-side (SSS), side-angle-side (SAS), or angle-side-angle (ASA) c

ongruence postulates?

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0
Here are the properties you should look out for. hope it's easier to understand! :)

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Kendrick’s math quiz grades are 90, 100, 48, 88, 100, and 96. Find the MEAN of Kendrick’s scores.
kipiarov [429]

Answer:

87

Step-by-step explanation:

The mean is 87, multipliy all the numbers then devide that number by 6!

4 0
3 years ago
How do you do this question?
likoan [24]

Answer:

a) -7/9

b) 16 / (n² + 15n + 56)

c) 1

Step-by-step explanation:

When n = 1, there is only one term in the series, so a₁ = s₁.

a₁ = (1 − 8) / (1 + 8)

a₁ = -7/9

The sum of the first n terms is equal to the sum of the first n−1 terms plus the nth term.

sₙ = sₙ₋₁ + aₙ

(n − 8) / (n + 8) = (n − 1 − 8) / (n − 1 + 8) + aₙ

(n − 8) / (n + 8) = (n − 9) / (n + 7) + aₙ

aₙ = (n − 8) / (n + 8) − (n − 9) / (n + 7)

If you wish, you can simplify by finding the common denominator.

aₙ = [(n − 8) (n + 7) − (n − 9) (n + 8)] / [(n + 8) (n + 7)]

aₙ = [n² − n − 56 − (n² − n − 72)] / (n² + 15n + 56)

aₙ = 16 / (n² + 15n + 56)

The infinite sum is:

∑₁°° aₙ = lim(n→∞) sₙ

∑₁°° aₙ = lim(n→∞) (n − 8) / (n + 8)

∑₁°° aₙ = 1

8 0
3 years ago
PLEASE HELP ME DEAR GOD<br> Find the solution to the system of equations.
Leviafan [203]
(-1,1)
This is because the solution is the point where the two lines meet.
3 0
2 years ago
Read 2 more answers
. If α and β are the roots of
Lostsunrise [7]

Answer:

18x^2+85x+18 = 0

Step-by-step explanation:

<u><em>Given Equation is </em></u>

=> 2x^2+7x-9=0

Comparing it with ax^2+bx+c = 0, we get

=> a = 2, b = 7 and c = -9

So,

Sum of roots = α+β = -\frac{b}{a}

α+β = -7/2

Product of roots = αβ = c/a

αβ = -9/2

<em>Now, Finding the equation whose roots are:</em>

α/β ,β/α

Sum of Roots = \frac{\alpha }{\beta } + \frac{\beta }{\alpha }

Sum of Roots = \frac{\alpha^2+\beta^2  }{\alpha \beta }

Sum of Roots = \frac{(\alpha+\beta )^2-2\alpha\beta   }{\alpha\beta  }

Sum of roots = (\frac{-7}{2} )^2-2(\frac{-9}{2} ) / \frac{-9}{2}

Sum of roots = \frac{49}{4} + 9 /\frac{-9}{2}

Sum of Roots = \frac{49+36}{4} / \frac{-9}{2}

Sum of roots = \frac{85}{4} * \frac{2}{-9}

Sum of roots = S = -\frac{85}{18}

Product of Roots = \frac{\alpha }{\beta } \frac{\beta }{\alpha }

Product of Roots = P = 1

<u><em>The Quadratic Equation is:</em></u>

=> x^2-Sx+P = 0

=> x^2 - (-\frac{85}{18} )x+1 = 0

=> x^2 + \frac{85}{18}x + 1 = 0

=> 18x^2+85x+18 = 0

This is the required quadratic equation.

5 0
3 years ago
Read 2 more answers
What are two steps are necessary to put this equation into standard form x^2 - 3x + 27 =8x- 3
Wittaler [7]

Answer:

you need to bring the 8x over then the -3

Step-by-step explanation:

X^2-3x+27=8x-3

X^2-11x+27=-3

x^2-11x+24

Is that what you are looking for??

Hope that helps feel free to ask more questions


Brainliest??

7 0
3 years ago
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