Answer:
the maximum population size that a particular environment can support.
Explanation:
A population can be defined as the total number of living organisms living together in a particular place and sharing certain characteristics in common.
Generally, these populations may be divided into a fraction of the population (subpopulation) based on certain factors and reasons.
Population regulation can be defined as a biological process that balances limiting factors affecting the growth of a population based on density. The factors that regulate the growth of a population are divided into two (2) main categories and these includes;
I. Density-independent factors.
II. Density-dependent factors.
Density-dependent are regulating factors such as predation, diseases, and competition that affect the size of the population of living organisms through decreasing or increasing mortality and birth rate.
Furthermore, density-independent factors do not have an increasingly greater effect as a population's density increases. Thus, its effect are reduced as a population's density increases in size.
Carrying capacity is the maximum population size that a particular environment can support. The carrying capacity of an environment is denoted by the letter k.
Both of its parents must have had a t gene
Answer: what I learned is that natural selection needs 4 things
Explanation:
over production
genetic variation
i don’t remember the rest but those are the main ones so that there’s lots of offspring in case some cant survive
HOPE I HELPED
Lactate is produced by fermentation
Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
