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3 years ago

For f(x)=4x+1 and g(x)=x^2-5, find (g/f)(x)

Mathematics

1 answer:

ddd [48]3 years ago

3 0

Answer:

$(g/f)(x) = \frac{g(x)}{f(x)} = \frac{ {x}^{2} - 5 }{4x + 1}$

I hope I helped you^_^

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Answer:

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Step-by-step explanation:

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Which statement about the simplified binomial expansion of (a + b)", where n is a positive integer, is true?

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$(a+b)^n ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + ..... +{n \choose n}a^{(0)}b^{(n)}$

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You multiply two integers. You increase one of them by 1 and decrease the other

snow_tiger [21]

Integers are numbers without decimals

The integers could you have multiplied are 9 and 2

Let the numbers be x and y

So, we have:

$\mathbf{x \times y}$

Increase x by 1 and reduce y by 1.

So, we have

$\mathbf{(x +1) \times (y -1) = 6 + xy }$

Open brackets

$\mathbf{xy -x + y - 1 = 6 + xy}$

Subtract xy from both sides

$\mathbf{ -x + y - 1 = 6}$

Collect like terms

$\mathbf{ -x + y = 6 + 1}$

$\mathbf{ -x + y = 7}$

Rewrite as:

$\mathbf{ y -x= 7}$

The above means that, the difference between the integers is 7.

There are several integers that fit the above <em>description</em>;

One possibility is: 9 and 2