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Eva8 [605]
3 years ago
8

Help plzAbcd(my choice is C)

Mathematics
1 answer:
-BARSIC- [3]3 years ago
8 0
The correct answer would be C.
Hope this helped!
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16w+2 simplified<br><br> Factor the expression by the greatest common factor
MatroZZZ [7]

Answer:

2(8w + 1)

Step-by-step explanation:

Look on either side of the plus sign. What ever you see that is common is a common factor. In this case it is also the greatest common factor.

2 appears on both sides of the plus sign.

2(16w/2 + 2/2)

4 0
2 years ago
Read 2 more answers
The square and the triangle have equal perimeters.
Tamiku [17]
I think not because a square has four sides and a triangle has three.
8 0
3 years ago
Polly's Polls asked 1850 second-year college students if they still had their original major. According to the colleges, 65% of
suter [353]

Answer:

The probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424

Step-by-step explanation:

The variable that assigns the value 1 if a person had its original major and 0 otherwise is a Bernoulli variable with paramenter 0.65. Since she asked the question to 1850 people, then the number of students that will have their original major is a Binomial random variable with parameters n = 1850, p = 0.65.

Since the sample is large enough, we can use the Central Limit Theorem to approximate that random variable to a Normal random variable, which we will denote X.

The parameters of X are determined with the mean and standard deviation of the Binomal that we are approximating. The mean is np = 1850*0.65 = 1202.5, and the standard deviation is √np(1-p) = √(1202.5*0.35) = 20.5152.

We want to know the probability that X is between 0.64*1850 = 1184 and 0.66*1850 = 1221 (that is, the percentage is between 64 and 66). In order to calculate this, we standarize X so that we can work with a standard normal random variable W ≈ N(0,1). The standarization is obtained by substracting the mean from X and dividing the result by the standard deviation, in other words

W = \frac{X-\lambda}{\sigma} = \frac{X-1202.5}{20.5152}

The values of the cummulative function of the standard normal variable W, which we will denote \phi are tabulated and they can be found in the attached file.

Now, we are ready to compute the probability that X is between 1184 and 1221. Remember that, since the standard random variable is symmetric through 0, then \phi(-z) = 1-\phi(z) for each positive value z.

P(1184 < X < 1221) = P(\frac{1184-1202.5}{20.5152} < \frac{X-1202.5}{20.5152} < \frac{1221-1202.5}{20.5152})\\ = P(-0.9018 < W < 0.9018) = \phi(0.9018) - \phi(-0.9018) = \phi(0.9018)-(1-\phi(0.9018))\\ = 2\phi(0.9018)-1 = 2*0.8212-1 = 0.6424

Therefore, the probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424.

Download pdf
4 0
3 years ago
A toy company produces 1,000 toys per
lidiya [134]
C option is correct. Because out of 10 toys 1 is defective. So 10 will be defective out of 100 and 100 will be defective out if 1000 i.e the monthly production.
8 0
3 years ago
2!7! Divided by 4!8! Simplified
Molodets [167]

Answer:

2/7 divided by 4/8 = 0.57142857142

3 0
3 years ago
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