H=-5(t^2 - 16t)
H=-5(t^2 - 16t +64)+320
H=-5(t-8)^2 +320
Vertex is at (8, 320)
The max height is 320 m.
4x^2 + 2x = -9
4x^2 + 2x + 9 = 0
remember that the form of quadratic is ax^2 + bx + c = 0
so
a = 4
b = 2
c = 9
Answer:
We accept H₀ , we do not have enought evidence for rejecting H₀
Step-by-step explanation:
Normal Distribution
sample size n = 60
standard deviation σ = 15
1.Hypothesis Test : Is a one tailed-test on the right
H₀ null hypothesis μ₀ = 50
Hₐ alternative hypothesis μ₀ > 50
2.-We will do the test for a significance level α = 0,01 tht means for a 99% interval of confidence
then z(c) = 2.32
3.- We compute z(s)
z(s) = [ ( μ - μ₀ ) /( σ/√n ) ⇒ z(s) = ( 2 * √60 ) / 15
z(s) = 15.49/15 ⇒ z(s) = 1.033
4.- We compare values of z(c) and z(s)
z(s) < z(c) 1.033 < 2.32
z(s) is in the acceptance region so we accept H₀ , we do not have enough evidence for rejecting H₀
Answer:
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Step-by-step explanation:
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