Find the solution to the system of equations below:
y = 4x + 20
y = 8x - 4
1 answer:
Answer:
(6, 44)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 4x + 20
y = 8x - 4
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 8x - 4 = 4x + 20
- Subtract 4x on both sides: 4x - 4 = 20
- Add 4 on both sides: 4x = 24
- Divide 4 on both sides: x = 6
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define equation: y = 8x - 4
- Substitute in <em>x</em>: y = 8(6) - 4
- Multiply: y = 48 - 4
- Subtract: y = 44
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Answer:
2500
Step-by-step explanation:
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The answer to the question is
False
There are 4 terms.
The second term and the fourth term have negative coefficients.
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Answer:
-5x+13 given (-x+3)-(4x-10)
Answer:-5x+13
Step-by-step explanation:
We are going to distribute to get rid of the ( ):
-x+3-4x+10
Pair up like terms:
-x-4x+3+10
Combine the like terms:
-5x+13