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Bingel [31]
3 years ago
13

There is a state that has 3 cities:

Mathematics
1 answer:
Mama L [17]3 years ago
7 0

Answer: b

Step-by-step explanation:

I took the test and got it right

good luck!

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What position did Theodore Roosevelt hold before he became president?
BlackZzzverrR [31]

Answer:

He served as Assistant Secretary of the Navy under President William McKinley

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3 0
3 years ago
Which algebraic expression is equivalent to the expression below?
noname [10]

Answer:

I think that the correct answer is B. 29k + 4

8 0
3 years ago
In the hyperbola graph,how do you find the domain and range?​
xxTIMURxx [149]

Step-by-step explanation:

<h2><em>y = ± 5⁄2 x</em></h2><h2><em>y = ± 5⁄2 xThe equation is the left half of the hyperbola. The domain is ( – ∞, – 1⁄5 ]. The range is ( – ∞, ∞ ). The vertical line test indicates that this is not the graph of a function.</em></h2>
3 0
3 years ago
There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t
beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

3 0
3 years ago
Which of the following statements is not true?
Daniel [21]

Answer:

3

Step-by-step explanation:

Those are factors of 9 not multiples

3 0
3 years ago
Read 2 more answers
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