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Natali [406]
2 years ago
6

HELP???????????????????????????????????????????????????????? pls? (10 points) (image down below to make it easier to understand.

)

Mathematics
2 answers:
prisoha [69]2 years ago
7 0

Answer:

Step-by-step explanation:

Jlenok [28]2 years ago
4 0
1 is 2 and 3 is 8 and the rest are 5-7
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Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discr
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Answer:

A quadratic equation can be written as:

a*x^2 + b*x + c = 0.

where a, b and c are real numbers.

The solutions of this equation can be found by the equation:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

Where the determinant is D = b^2 - 4*a*c.

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then the solutions are:

x = \frac{-b +- R }{2*a}

Where each sign of R is a different solution for the equation.

If D< 0, we have the square root of a negative number, then we have a complex component:

√D = i*R

x = \frac{-b +- C*i }{2*a}

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If D = 0

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