Based on the shape shown on the graph, the reflection of the shape would be b) A coordinate grid is shown from positive 8 to negative 8 on the x-axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair 2, negative 2 and 4, negative 2, and 2, negative 6.
<h3>What shape is the reflection?</h3>
The coordinate grid that the shape would be reflected across is the y axis to get a reflection in the negative side of the x axis.
The first reflection would be of the point that is (2,2). It would be reflected to become (-2, 2).
The second reflection would be of point (2, 6) which would then be reflected to become (-2, 6).
Finally the third point would be of point (4, 2) which would then become (-4, 2).
In conclusion, the reflection was across the y axis.
Options include:
- a) A coordinate grid is shown from positive 8 to negative 8 on the axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair negative 2, 2 and negative 4, 2 and negative 4, 6.
- b) A coordinate grid is shown from positive 8 to negative 8 on the x-axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair 2, negative 2 and 4, negative 2, and 2, negative 6.
- c) A coordinate grid is shown from positive 8 to negative 8 on the axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair negative 2, 2 and negative 2, 4 and negative 6, 2.
- d) A coordinate grid is shown from positive 8 to negative 8 on the axis and from positive 8 to negative 8 on the y-axis. A triangle is shown on ordered pair 2, negative 2 and 2, negative 4 and 6, negative 2.
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Answer:
5 x 2 ( 3 x + 2 )
Step-by-step explanation:
Answer:
60 mph
Step-by-step explanation:
You divide 180 by 3 to get 60 mph
De l'Hospital rule applies to undetermined forms like
If we evaluate your limit directly, we have
which is neither of the two forms covered by the theorem.
So, in order to apply it, we need to write the limit as follows: we start with
Using the identity , we can rewrite the function as
Using the rule , we have
Since the exponential function is continuous, we have
In other words, we can focus on the exponent alone to solve the limit. So, we're focusing on
Which we can rewrite as
Now the limit comes in the form 0/0, so we can apply the theorem: we derive both numerator and denominator to get
So, the limit of the exponent is -6, which implies that the whole expression tends to
Step-by-step explanation:
yes