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3 years ago

Write -3i + (3/4+2i) - (9/3+3i) as a complex number in standard form

Mathematics

1 answer:

bogdanovich [222]3 years ago

4 0

Answer:

= -3i + (3/4+2i) - (9/3+3i)

= (3/4 - 9/3) + (-3 + 2 -3)i

= -9/4 -4i

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Solve for p.<br><br> 2(p + 1) = 24

tensa zangetsu [6.8K]

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Marysya12 [62]

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A sample of tritium-3 decayed to 94.5% of its original amount after a year.

Zolol [24]

(a) If $y(t)$ is the mass after $t$ days and $y(0) = A$ then $y(t) = Ae^{kt}.$

$y(1) = Ae^k = 0.945A \implies e^k = 0.945 \implies k = \ln 0.945$

$\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\ ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\
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(b)
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3 years ago

Rosie washes clothes for two families the first family pays her $500 more per month than the second. Her total earning per month

disa [49]

Answer:

Family 1: $1.850
Family 2: $1.350

Step-by-step explanation:

We know that the total monthly payment is 3200, so if we call Pa (family A`s payment) and Pb (Family B's payment) the payments:

Pa+Pb=3200
also, Pa = Pb+500

So if we replace Pa in the first ecuation:

Pb+500+Pb=3200
2Pb= 3200-500
Pb=2700/2= $1.350

then Pa+Pb=3200 => Pa= 3200-1350= $1.850

Good Luck!

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3 years ago