Question

coins are to be put into 7 pocket so that each pocket contain at least one coins and no of two of remaining pocket are to contain an equal number of coins. what is least possible number of coins needed for pockets?​

Answer 1

Answer:

We want to minimize the number of coins. Since there must be AT LEAST 1 coin per pocket, let's put 1 coin in the first 3 pockets.

Pocket #1: 1 coin

Pocket #2: 1 coin

Pocket #3: 1 coin

No two of the remaining pockets are to contain an equal number of coins.

So, from this point on, we cannot put 1 coin in any more pockets (otherwise, we'll break the rule about no more than 3 pockets containing the same number of coins).

To minimize the number of coins, we'll put 2 coins in pocket #4, then 3 in pocket #5 and so on...

Pocket #4: 2 coins

Pocket #5: 3 coins

Pocket #6: 4 coins

Pocket #7: 5 coins

So, the minimum number of coins = 1+1+1+2+3+4+5 =17

the answer is 17

Explanation:

hope this helps you