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tatuchka [14]
2 years ago
8

coins are to be put into 7 pocket so that each pocket contain at least one coins and no of two of remaining pocket are to contai

n an equal number of coins. what is least possible number of coins needed for pockets?​
SAT
1 answer:
german2 years ago
5 0

Answer:

We want to minimize the number of coins. Since there must be AT LEAST 1 coin per pocket, let's put 1 coin in the first 3 pockets.

Pocket #1: 1 coin

Pocket #2: 1 coin

Pocket #3: 1 coin

No two of the remaining pockets are to contain an equal number of coins.

So, from this point on, we cannot put 1 coin in any more pockets (otherwise, we'll break the rule about no more than 3 pockets containing the same number of coins).

To minimize the number of coins, we'll put 2 coins in pocket #4, then 3 in pocket #5 and so on...

Pocket #4: 2 coins

Pocket #5: 3 coins

Pocket #6: 4 coins

Pocket #7: 5 coins

So, the minimum number of coins = 1+1+1+2+3+4+5 =17

the answer is 17

Explanation:

hope this helps you

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The example of "happy violence" that George Gerbner describes is c. Mean-world syndrome.

<h3>What is the mean-world syndrome?</h3>

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2 years ago
~A certain rectangular prism has a height of h inches, a width that is 3 inches less than its height, and a length that is 4 inc
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Answer:

Volume = 480 cubic inches

Explanation:

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Setting (1) = (2) gives

h² + h -12 =60

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h - 8 = 0 ==> h = 8

Since h cannot be negative, h = 8 inches

Volume = base area x h = 60 x 8 = 480 cubic inches

<u>Note</u>

We do not have to calculate length and width separately, but if so,

w = 8 -3 = 5

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3 0
2 years ago
A linear machine is connected as shown in Fig. 1. The input source voltage Vin=10V, the internal resistance Rin=0.05Ω. The appli
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Recall that Force (f) = il xB

Given that Force (F) = 10N; and

Magnetic Field Density B = 0.5T

Hence,

10 = i x 0.2 x 0.5  

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Given that the current being supplied is  in DC hence the machine is a generator. [Vdc x i]

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The electric power of the source is:

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8 0
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Answer:

Ummmm..

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