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aleksandr82 [10.1K]
3 years ago
14

If the Discriminant of an equation is zero, which of the following is true of the equation?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
5 0

Answer:

a) it has one real solution

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Round each number to the nearest ten and estimate the sum.
Katen [24]
I think its a. Good luck!
6 0
2 years ago
phillip bought 12 used cds and dvds.cds cost $2 each,and dvds cost $3 each.he spent $31,not including tax.how many dvds did phil
inessss [21]
Let c and d be the number of cds and dvds respectively.

c+d=12

c=12-d

The we are told that:

2c+3d=31, using c found above in this equation gives you:

2(12-d)+3d=31

24-2d+3d=31  

24+d=31

d=7

So Phillip bought 7 dvds.

check...

3*7+2(12-7)=31

21+2(5)=31

21+10=31

31=31
8 0
3 years ago
Someone plz help me :(
saul85 [17]

the answer is A

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4 0
2 years ago
Read 2 more answers
Refer to the image i couldnt copy it so the image is the quesstion<br><br> answer in true or false
Irina18 [472]

The sign of "b" on the numerator should be negative. So we conclude that the correct option is false.

<h3>Is the equation in the image correct or incorrect?</h3>

For a quadratic equation of the form:

y = a*x^2 + b*x + c

By using the Bhaskara's formula, the solutions of the equation:

0 = a*x^2 + b*x + c

Are given by the formula:

x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}

Notice that the sign of the first term on the numerator should be negative, while on the image it is positive.

So the equation shown in the image is incorrect.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

6 0
2 years ago
Find the Center and the radius of the circle<br> x2 + y2 - 6x + 8y- 7 = 0.
777dan777 [17]

Answer:

C(3,-4), r=4*sqrt(2)

Step-by-step explanation:

C(p, q)

x^2+y^2+dx+ey+f=0

p=-d/2, q=-e/2, r^2=p^2+q^2-f

x^2+y^2 - 6x+8y-7=0

p=-(-6)/2=6/2=3

q=-8/2=-4

r^2=3^2 +(-4)^2+7

r^2=9+16+7

r^2=32

r=sqrt(32)

r=sqrt(16*2)

r=4*sqrt(2)

8 0
3 years ago
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