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Damm [24]
2 years ago
10

Por favor es para hoy. El papá de Rafael va a construir una piscina afuera de su casa en forma de un cuadrado con el área de 121

2 . Alrededor de la piscina quiere construir una plataforma de cuatro pies de ancho. Explícale a Rafael paso a paso como calcular el perímetro de la plataforma. Tu explicación debe incluir un dibujo de la piscina y la plataforma.
Mathematics
1 answer:
nydimaria [60]2 years ago
5 0

Answer:

For an inground pool, a patio area ranges between $3 and $40 per square foot. That wide range depends largely on the materials you use to build the space.

Para una piscina enterrada, el área de un patio varía entre $ 3 y $ 40 por pie cuadrado. Esa amplia gama depende en gran medida de los materiales que utilice para construir el espacio.

Step-by-step explanation:

pls give me brainliest

por favor, dame lo más inteligente

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How do we solve this problem?
MaRussiya [10]
To solve the problem you must find the area of every square. For F one of the squares has a side length of 3 and because this is a square the other sides are also 3. To find the area we multiply two of the sides so 3 times 3 is 9
You do this with both the other squares
3*3=9
4*4=16
The area of the large square is given as 25
So 9+16=25 which means this is not the correct answer

H.
9*9=81
Given as 144
The area of the large square is 21*21 which is 441
144+81= 225
So because the two small squares DO NOT equal the area of the large square this is the correct answer.
5 0
3 years ago
Flying to Kimpala with a tail wind a plane averaged 158km/hr. On the return trip the plane only average 112km/hr. While flying b
lora16 [44]

The speed of wind and speed of plane in still air  are  23  and  135 km/h respectively.

<u>Step-by-step explanation:</u>

Let the speed of wind and speed of plane in still air  are  w  and  p km/h respectively.  

The effective speed on onward journey was  

p+w=158  ................(1)

The effective speed on return journey was  

p-w=112 ..............(2)

Adding equation (1) and equation (2) we get,  

⇒ (p+w)+(p-w) = 158+112

⇒ 2p = 270

⇒ p = 135

Putting value of p = 135 in p+w=158 we get:

⇒ p+w=158

⇒ 135+w=158

⇒ w=23

Therefore ,The speed of wind and speed of plane in still air  are  23  and  135 km/h respectively.

3 0
2 years ago
Please help, brainly for whoever gets it done first, correct answers please
lesya [120]

Answer:

-875/79

Step-by-step explanation:

4 0
3 years ago
Edward wrote a pattern starting at 0 and following the rule "add 2." . Juan wrote a pattern starting at 0 and following the rule
joja [24]

Answer:

the third option

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Cobalt-60 has a half-life of about 5 years. How many grams of 300 g sample well remain after 20 years?
Crank
20/5 = 4 half lives

so 

<span>300 * (1/2)^4
</span>= 300 * 0.0625
=18.75 grams



5 0
3 years ago
Read 2 more answers
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