A basketball team scored a total of 1470 points over the course of its 21-game season. 470 of the points were from 1-point baske
ts. The remaining points were either 2-point or3-point baskets. There were 440 2-point or 3-point
baskets scored. How many of those 440 baskets were 3-point baskets?
To solve this you'll want to set up a system of equations.
Since there were 1470 points scored total, and 470 of them were from 1 point baskets, that means 1470-470 = 1000 points were scored by 2 and 3 point baskets. Assuming x = the number of 2 point baskets scored and y = the number of 3 point baskets scored, that gives us an equation of 2x + 3y = 1000.
We also know that there were a total of 440 2 or 3 point baskets scored. Using x and y as defined before, we get an equation of x + y = 440.
To solve this, we can use substitution. Let's solve for x in terms of y for the second equation.
So x + y = 440. If we subtract y from both sides, we get x = 440 - y. Now we substitute 440 - y for x in the first equation.
2*(440-y) + 3y = 1000. Now we simply solve the equation. 880 - 2y + 3y = 1000. 880 + y = 1000. y = 120.
So 120 of the baskets scored were 3 point baskets.
If we want to solve for x, we can substitute in the known value of y to the first equation x + 120 = 440. x = 320.
So 320 of the baskets scored were 2 point baskets.
