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faltersainse [42]
2 years ago
6

PLEASE THERE IS THIS GIRL THAT NEED THE AWNSERS HELP ME GUYS

Mathematics
2 answers:
Bad White [126]2 years ago
7 0

Answer:

1 at theorigain

2 5/6

3 1,1

4 4

Step-by-step explanation:

whos the girl

blake

(i got ur name of ur paper btw)

Karo-lina-s [1.5K]2 years ago
7 0

Answer:

1 at the origin

2 5/6

3 1,1

4 4

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How do u solve y=2/3x-4
poizon [28]
The answer is 2 y= 2 so 3•2=6 6-4=2
4 0
3 years ago
Tent: If a function f has an inverse and f(-3) = 6, then f-1(6)
Dvinal [7]
I’m tryna look for that too
4 0
3 years ago
Read 2 more answers
20 POINTS PLZ HELP!!!!!!!!!!!!!!!!!!!!
mars1129 [50]

Answer:

a = 15

Step-by-step explanation:

First, you have to combine like terms: 5a and 3a, -5, -15, 6, and 4.

You can do it in any order and you will always get a = 15 for your answer.

Hope this helps!!!

3 0
3 years ago
Read 2 more answers
Figure ABCD is a rhombus where the m∠ABC = 84 and m∠ABE = 3x − 6. Solve for x. Rhombus ABCD with diagonals AC and BD and point E
bazaltina [42]

Answer:

<u> x = 16</u>

Step-by-step explanation:

See the attched figure

We should know that, one of the properties of the rhombus is the diagonals bisect the angles of the rhombus.

Given:

m∠ABC = 84  and m∠ABE = 3x − 6

So, m∠ABE = 0.5 * m∠ABC = 0.5 * 84 = 42

∴ 3x - 6 = 42

Solve for x

3x = 42 + 6 = 48

x = 48/3 = 16

<u>∴ x = 16</u>

4 0
3 years ago
Read 2 more answers
1) What is the solution of the given system?
m_a_m_a [10]

Answer:

1  x=-2.5  y = -5.5

2.  x=5  y=1

Step-by-step explanation:

1) What is the solution of the given system?

5x-y=-7

3x-y=-2

Multiply the second equation by -1

-1*(3x-y)=-1(-2)

-3x +y = 2


Now add the first equation to the modified second equation

5x-y=-7

-3x +y = 2

------------------

2x = -5

Divide each side by 2

2x/2 = -5/2

x = -2.5

Now we need to find y

-3x+y =2

-3(-2.5) +y =2

7.5 +y =2

Subtract 7.5 from each side

7.5 -7.5 +y =2-7.5

y = -5.5


2) what is the solution of the given system?

5x+7y=32

8x+6y=46

Divide the second equation by 2

8x/2+6y/2=46/2

4x+3y =23


Multiply the first equation by 4

4 (5x+7y)=32*4

20x+28y = 128


Now multiply the modified 2nd equation by -5

-5(4x+3y )=-5(23 )

-20x -15y = -115


Lets add the new equations together to eliminate x

20x+28y = 128

-20x -15y = -115

---------------------

      13y = 13

Divide each side by 13

13y/13 =13/13

y=1

Now substitute back in to find x

5x+7y=32

5x +7(1) =32

5x +7 =32

Subtract 7 from each side

5x+7-7 =32-7

5x =25

Divide by 5

5x/5 =25/5

x=5





3 0
3 years ago
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