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2 years ago

PLS HELP IM CONFUSED

Mathematics

1 answer:

Ostrovityanka [42]2 years ago

4 0

Easiest way to solve this is to try plugging in the values from the table into the equations

Let’s try y = x + 4

The first coordinates from the table says
(-9 , -5 )

-5 = -9 + 4
-5 = -5

They match, so y = x + 4 is the right answer. You can try plugging in the other variables if your still uncertain

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Amanda and Stephen wrote the following proofs to prove that vertical angles are congruent. Who is correct? Line segment NT inter

jolli1 [7]

In fact, both Amanda's and Stephen's profs are correct; they are just using different supplementary angles. Amanda's is using the supplementary angles ∠1 and ∠4, and ∠3 and ∠4, whereas Stephen is using ∠1 and ∠2, and ∠2 and ∠3. Please check the picture to visualize this more effectively.

6 0

3 years ago

Read 2 more answers

How many solutions does the equation have?

Salsk061 [2.6K]

Answer: there is only one solution

Step-by-step explanation:

Combine like terms by performing the opposite operation of subtracting 4x on both sides of the equation

The 4x's will cross out on the right

4x - 4x = 0x = 0

On the left:

2x - 4x = -2x

Now the equation looks like:

-2x + 3 = 2

Continue to combine like terms by subtracting 3 on both sides of the equation

On the left:

3 - 3 = 0

On the right:

2 - 3 = -1

Equation:

-2x = -1

Isolate x by performing the opposite operation of dividing -2 on both sides of the equation

On the left:

-2x ÷ -2 = 1

On the right:

-1 ÷ -2 = 1/2

x= 1/2

4 0

3 years ago

Read 2 more answers

Last question...! And then I’m totally done with asking questions for a while. -v-;; Any answers or advice on how to solve?

Veseljchak [2.6K]

Multiply both sides by "x"

1 -x + 2x = 7

x = 6

6 0

3 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

Answer:

3003 number of 5-member chess teams can be chosen from 15 interested players.

Step-by-step explanation:

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$