Answer:
40 drops
Approximately 0.166 %
Step-by-step explanation:
It would be easier to work the same units for volume
Since there are 1000 ml in a liter
Original water volume 1.2 L = 1.2 x 1000 = 1200 mLl
The final volume of the acid-water solution = 1.202 L = 1202 mL
So total volume of acid added = 1202-1200 = 2 mL
Each drop of acid is 0.05 mL
Number of drops added = 2/.05 = 40 drops
Percent of acid in acid solution = (Volume of acid added)/(Final volume) x 100 = (2/1202) ≈ 0.00166 x 100 ≈ 0.166 %
Answer:
5 dollar intervals
Step-by-step explanation:
The answer is A. The data is a sample, so you can determine every answer with the word 'population' in it to be wrong.
5c + 3 - 2c + 5
5c - 2c + 3 + 5
3c + 8 ~~~
