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beks73 [17]
3 years ago
8

Assume that the profit generated by a product is given by where x is the number of units sold. If the profit keeps changing at a

rate of per month, then how fast are the sales changing when the number of units sold is 1100? (Round your answer to the nearest dollar per month.) $30/month $132,665/month $16,583/month $33,166/month
Mathematics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

P'(1100)=0.06

(see explanation below)

Step-by-step explanation:

<em>The answer is incomplete. The profit function is missing, but another function will be used as an example (the answer will not match with the options). </em>

<em>The profit generated by a product is given by </em>P=4\sqrt{x}<em>.</em>

The changing rate of sales can be mathematically expressed as the derivative of the profit function.

Then, we have to calculate the derivative in function of x:

\dfrac{dP}{dx}=\dfrac{d[4x^{0.5}]}{dx}=4(0.5)x^{0.5-1}=2x^{-0.5}=\dfrac{2}{\sqrt{x}}

We now have to evaluate this function for x=1100 to know the rate of change of the sales at this vlaue of x.

P'(1100)=\frac{2}{\sqrt{1100} } =\frac{2}{33.16} =0.06

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Answer:

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Step-by-step explanation:

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The quadratic formula is:

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Putting values in formula and finding x

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So, Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

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2 years ago
joan is rolling a six— sided numbers cube with 1—6 on the sides. what is the probability that she will roll a numbers less tha 3
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Answer:

The statement is false.

Step-by-step explanation:

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The correct statement would be:

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