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Yuliya22 [10]
3 years ago
12

Based on the activity series you created in part C, predict whether there would be a chemical

Chemistry
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

I dont know

Explanation:

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Until the 1500s, doctors thought
Oliga [24]

Answer:

D

Explanation:

6 0
3 years ago
Consider the reaction of ethyl acetate with sodium hydroxide: CH3COOC2H5(aq)+NaOH(aq)⇌CH3COONa(aq)+C2H5OH(aq) The reaction is fi
Alexus [3.1K]

Answer: The rate law is rate=k[CH_3COOC_2H_5]^1[NaOH]^1

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

For the given reaction:

CH_3COOC_2H_5(aq)+NaOH(aq)\rightleftharpoons CH_3COONa(aq)+C_2H_5OH(aq)

k= rate constant

Rate law: rate=k[CH_3COOC_2H_5]^x[NaOH]^y

For the given rate law:

y =1 =  order with respect to NaOH

n = total order = 2

2= (x+y)

2= (x+1)

x= 1

Thus order with respect to CH_3COOC_2H_5 is 1 and rate law is : rate=k[CH_3COOC_2H_5]^1[NaOH]^1

6 0
3 years ago
Determine the number of particles in 1 mole of dust mites.
OLEGan [10]
D is the answer. It is the avagadro's constant
3 0
4 years ago
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Suppose 20.23 g of glucose are dissolved in 95.75 g of water at 27.0 OC. Glucose is nonvolatile (has no vapor pressure) and has
leonid [27]

Answer:

Explanation:

From the information given :

we can understand the solute is glucose and the solvent is water,

So, the weight of glucose = 20.23 g

the molecular weight of glucose = 180.2 g/mol

weight of water = 95. 75 g

the molecular weight of water = 18.02 g/mol

pure vapor pressure of water P_A = 26.7 \ mmHg at 27°C

moles of glucose = weight of glucose/ molecular weight of glucose

= 20.23/180.2

= 0.11 mole

moles of water =  weight of water / molecular weight of water

= 95.75/18.02

= 5.31 mole

mole fraction of glucose X_{glucose} = (moles of glucose)/(moles of glucose+ moles of water)

X_{glucose} = 0.11/(0.11 + 5.31)

X_{glucose} =  0.0203

mole fraction of glucose X_{water} = (moles of water)/(moles of water+ moles of glucose)

X_{water} = 5.31/ (5.31 + 0.11)

X_{water} =  0.9797

Using Raoult's Law:

P_S = P^0_A \times X_A \  \ \  OR  \  \ \  P_A = P^0_A \times X_A

where:

P_S = vapor pressure of the solution

P_A = total vapor pressure of the solution

P^0_A= vapor pressure of the solvent in the pure state

X_A = mole fraction of solvent i.e. water

P_A = 95.75 ×  0.9797

P_A =  93.81 mmHg

the total vapor pressure of the solution = 93.81 mmHg

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What can I expect on the asvab
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Which situation is an example of internal conflict
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