Answer:
I'm pretty sure it's neutrons the first one
Answer:
Empirical formula is KHO₃C.
Explanation:
Given data:
Percentage of potassium = 39.0%
Percentage of hydrogen = 1.01%
Percentage of carbon = 12.0%
Percentage of oxygen = 47.9%
Empirical formula = ?
Solution:
Number of gram atoms of K = 39.0/ 39 = 1
Number of gram atoms of H = 1.01 / 1.01 = 1
Number of gram atoms of O = 47.9 / 16 = 3
Number of gram atoms of C = 12 / 12 = 1
Atomic ratio:
K : H : O : C
1/1 : 1/1 : 3/1 ; 1/1
1 : 1 : 3 : 1
K : H : O :C = 1: 1 : 3 : 1
Empirical formula is KHO₃C.
Hihi!
The correct answer is B. The mass number of this nuclide is 131! It's proton number is 56 and it has 75 neutrons (131 - 56 = 75 neutrons).
I hope I helped!
-Jailbaitasmr
Answer:
10.5 moles of Nitrogen gas is produced
Explanation:
Number of moles = mass / molar mass
molar mass of Nitrogen = 14g/mol
mass produced= 147g
moles= 147/14= 10.5moles of Nitrogen gas produced
