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Akimi4 [234]
3 years ago
14

The graph of linear function k passes through the points (-3, 0) and (1, 8). Which statement must be true?

Mathematics
2 answers:
grin007 [14]3 years ago
4 0

Answer:

  • B. The slope of the graph of k is 2.

Step-by-step explanation:

<h3>Find the equation of the line.</h3>

<u>The slope is:</u>

  • m = (8 - 0)/(1 + 3) = 2

<u>The y-intercept is:</u>

  • 0 = -3*2 + b
  • b = 6

<u>The line is:</u>

  • y = 2x + 6
<h3>Now lets look at the answer options</h3>

A. <u>The x-Intercept of the graph of k is 8.</u>

  • The x- intercept is -3, False

B. <u>The slope of the graph of k is 2.</u>

  • m = 2, True

C. <u>The graph of k passes through (-1, -8).</u>

  • -8 = 2(-1) + 6
  • -8 = 4, False

D. <u>The zero of k is 3.</u>

  • x = 0 ⇒ y = 0+ 6 = 6,  False
lisabon 2012 [21]3 years ago
3 0

Option B

Let's verify

Slope of graph:-

\\ \sf\longmapsto m=\dfrac{8-0}{1+3}

\\ \sf\longmapsto m=\dfrac{8}{4}

\\ \sf\longmapsto m=2

Hence k=2(Proved)

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Answer:

1) The mean calculated for this case is \bar X=61.5

2)  61.5-5.4=56.1

3) 61.5+5.4=66.9

4) B. An interval estimate gives us a sense of the accuracy of the point estimate whereas a point estimate alone does not.

Because with the confidence interval we know the confidence level of the interval, and the limits for the parameter at some significance level.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part 1

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (a)  

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The mean calculated for this case is \bar X=61.5

The sample deviation calculated s=5.143

\mu population mean (variable of interest)

n=6 represent the sample size  

Part 2

The confidence interval for the mean is given by the following formula:

\bar X \pm ME   (1)

So if we have the margin of error 5.4mm we can find the lowr limit like this:

61.5-5.4=56.1

Part 3

61.5+5.4=66.9

Part 4

B. An interval estimate gives us a sense of the accuracy of the point estimate whereas a point estimate alone does not.

Because with the confidence interval we know the confidence level of the interval, and the limits for the parameter at some significance level.

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Manuela solved the equation 3−2|0.5x 1.5|=2 for one solution. her work is shown below. 3−2|0.5x 1.5|=2 −2|0.5x 1.5|=−1 |0.5x 1.5
irakobra [83]

The other solution to the absolute value equation 3 − 2|0.5x + 1.5| = 2 is x = -4

<h3>How to determine the solution?</h3>

The equation is given as:

3 − 2|0.5x + 1.5| = 2

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