Answer: C.
Step-by-step explanation:
if they deleat the answer im sorry
Answer:
4/25
Step-by-step explanation:
Answer:
$36 400
Step-by-step explanation:
Step 1
The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.
The amount deposited in January is ![\$100.](https://tex.z-dn.net/?f=%5C%24100.)
The amount deposited in February is ![1\$00\times 3= \$300.](https://tex.z-dn.net/?f=1%5C%2400%5Ctimes%203%3D%20%5C%24300.)
The amount deposited in March is ![\$300\times 3= \$900.](https://tex.z-dn.net/?f=%5C%24300%5Ctimes%203%3D%20%5C%24900.)
The amount deposited in April is ![\$900\times 3= \$2\700.](https://tex.z-dn.net/?f=%5C%24900%5Ctimes%203%3D%20%5C%242%5C700.)
The amount deposited in May is ![\$2\,700\times 3= \$8\,100.](https://tex.z-dn.net/?f=%5C%242%5C%2C700%5Ctimes%203%3D%20%5C%248%5C%2C100.)
The amount deposited in June is ![\$8\,100\times 3= \$24\,300.](https://tex.z-dn.net/?f=%5C%248%5C%2C100%5Ctimes%203%3D%20%5C%2424%5C%2C300.)
Step 2
The next step is to add up all the money that was deposited into the account. This calculation is shown below,
![\$100+\$300+900+\$\$2\,700+\$8\,100+\$24\,000=\$36\,400](https://tex.z-dn.net/?f=%5C%24100%2B%5C%24300%2B900%2B%5C%24%5C%242%5C%2C700%2B%5C%248%5C%2C100%2B%5C%2424%5C%2C000%3D%5C%2436%5C%2C400)
I’m pretty sure it’s Linear decreasing
Answer:
Harrison method results in more money after 2 years
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
Harrison Method
![t=2\ years\\ P=\$300\\ r=0.02\\n=12](https://tex.z-dn.net/?f=t%3D2%5C%20years%5C%5C%20P%3D%5C%24300%5C%5C%20r%3D0.02%5C%5Cn%3D12)
substitute in the formula
![A=\$300(1+\frac{0.02}{12})^{12*2}=\$312.23](https://tex.z-dn.net/?f=A%3D%5C%24300%281%2B%5Cfrac%7B0.02%7D%7B12%7D%29%5E%7B12%2A2%7D%3D%5C%24312.23)
Sherrie Method
substitute in the formula
![A=\$200(1+\frac{0.04}{4})^{4*2}=\$216.57](https://tex.z-dn.net/?f=A%3D%5C%24200%281%2B%5Cfrac%7B0.04%7D%7B4%7D%29%5E%7B4%2A2%7D%3D%5C%24216.57)
therefore
Harrison method results in more money after 2 years