Answer:
Graph B
The graph in the attached figure
Step-by-step explanation:
we have
This is a exponential function
of the form
where
a is the initial value
b is the base
r is the rate
b=1+r
In this problem
a=2 ----> the y-intercept
b=3
so
1+r=3 -----> r=3-1=2 -----> r=200%
so
The y-intercept of the graph is equal to 2
As x increases the value of f(x) increases
therefore
Graph B
Answer:
b = 14-4
Step-by-step explanation:
Let the number of black bugs be b
Let the number of green bugs be g
If 14 bugs are crawling on the step, then;
b + g = 14 ....1
If there are 4 green bugs, then g = 4
Substitute g = 4 into the equation
b + g = 14
b + 4 = 14
b = 14 - 4
Hence the sentence that can be required to find the number of black bugs is b = 14-4
Answer:
729 tiles
Step-by-step explanation:
27 x 27 = 729
729 /1 =729
Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s
