Differentiate:
-5×2(xe^x^2)y-5e^x^2dy/dx=1
-5e^x^2(2xy+y´)=1
When x=-5, y=0:
-5e²⁵y´=1, so y´(-5)=-eˉ²⁵/5
Answer:
Yes
Step-by-step explanation:
The larger side is smaller than the other sides combined
(2 + 13) > 14
Hope this helps
Answer:
45
Step-by-step explanation:
AEF is a similar triangle to ABC. that means it has the same angles, and the sides (and all other lines in the triangle) are scaled from the ABC length to the AEF length by the same factor f.
now, what is f ?
we know this from the relation of AC to FA.
FA = 12 mm
AC = 12 + 28 = 40 mm
so, going from AC to FA we multiply AC by f so that
AC × f = FA
40 × f = 12
f = 12/40 = 3/10
all other sides, heights, ... if ABC translate to their smaller counterparts in AEF by that multiplication with f (= 3/10).
the area of a triangle is
baseline × height / 2
aABC = 500
and because of the similarity we don't need to calculate the side and height in absolute numbers. we can use the relative sizes by referring to the original dimensions and the scaling factor f.
baseline small = baseline large × f
height small = height large × f
we know that
baseline large × height large / 2 = 500
baseline large × height large = 1000
aAEF = baseline small × height small / 2 =
= baseline large × f × height large × f / 2 =
= baseline large × height large × f² / 2 =
= 1000 × f² / 2 = 500 × f² = 500 ×(3/10)² =
= 500 × 9/100 = 5 × 9 = 45 mm²
8/40=?/120 40x3=120 8x3=24 so 24 pages or 24/120
Answer: h= 69.3m
Step-by-step explanation:
The correct values in the question are:
year : 2006, length 62, vertical height 62.
So, the measure asked is called slant height . we have to apply the formula:
sh = √(vh^2 + [L/2]^2)
Where:
vh= vertical height
L= length of a side of the square base
Replacing with the values given:
sh= √(62^2 + [62/2]^2)
sh = √(3,844 + 31^2)
sh= √(3,844 + 961)
sh = √4,805
hs= 69.31 =69.3 m (nearest tenth)
Since in the question that height is called h, h= 69.3
