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3 years ago

Please help me I’m having so much trouble I need ASAP I’m stressing :(

Mathematics

1 answer:

Elis [28]3 years ago

8 0

Answer:

1000 (1.12)^t

Step-by-step explanation:

first year 1120

second year 1254.4

etc

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Wes has a piece of land with side lengths of 36.2 m, 41.6 m, 39.4 m, and 31.2 m. He also has 150 m of tape to mark the boundarie

Lesechka [4]

Add up all of the side lengths and you get 148.4 as the perimeter.

subtract that from 150 and you're left with 1.6 m left of tape

3 0

4 years ago

Read 2 more answers

Geri jogs every fourth day. Sarah jogs along the same path every fifth day. Both girls jog on the path on July 7. What is the ne

Colt1911 [192]

Answer:

The next day they will both run on the path is July 27th.

We can find this by making columns writing every date and seeing when they intersect.

4 5

8 10

12 15

16 20

We can then add this to the current date to find the date they will next run together.

Step-by-step explanation:

hope this helps. . . <3

good luck! UwU

8 0

2 years ago

Please help me and make sure to round the answers to the nearest hundred. I’ll give you brainiest!

mars1129 [50]

Answer:

add 2 zeros at the end of all of them

Step-by-step explanation:

3 0

3 years ago

If A=(0,0) and B=(8,2), what is the length of AB

NeX [460]

Answer:

$\boxed{\sf Distance_{AB}= 8.24 \ units }$

Step-by-step explanation:

Here two points are given to us and we need to find the distance between the two points . The given points are , A(0,0) and B(8,2) . The distance between the two points can be found out using the Distance Formula , which is ,

Distance Formula:-

$\sf\implies \green{ Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}}$

Therefore on substituting the respective values ,we can find the Distance as ,

$\sf\longrightarrow Distance = \sqrt{ ( 0 - 8)^2 + (0-2)^2}$

Simplify the brackets ,

$\sf\longrightarrow Distance =\sqrt{ (-8)^2+(-2)^2}$

Square the numbers inside the squareroot ,

$\sf\longrightarrow Distance =\sqrt{ 64 + 4}$

Add the numbers inside the squareroot ,

$\sf\longrightarrow Distance = \sqrt{68}$

Find the value of squareroot,

$\sf\longrightarrow \boxed{\blue{\sf Distance = 8.24 \ units }}$

Hence the distance between the two points is 8.24 units .

3 0

3 years ago

HELP ASAP PLEASE!!!

grigory [225]

The quadratic fomula:

$ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\If\ \Delta0,\ then\ \boxed{TWO\ SOLUTIONS:\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}}-----------------------------------------------$

We have the equation:

$2x^2-7x-21=0\\\\a=2,\ b=-7,\ c=-21\\\\\Delta=(-7)^2-4(2)(-21)=49+168=217 > 0\\\\x_1=\dfrac{-(-7)-\sqrt{217}}{2(2)}=\dfrac{7-\sqrt{217}}{4}\approx-1.93\\\\x_2=\dfrac{-(-7)+\sqrt{217}}{(2)(2)}=\dfrac{7+\sqrt{217}}{4}\approx5.43\\\\Answer:\ \boxed{\boxed{2.\ -1.93\ and\ 5.43}}$

7 0

3 years ago