Answer:
22.3 ft
Step-by-step explanation:
we know the base is 36 ft and we want to know the height. We know the angle of elevation
AC is you picture is 36 and we are looking for BC
We know angle A is 25
We will use tangent
tan A = opposite side/ adjacent side
tan A = BC/AC
tan 25 = BC/36
Multiply each side by 36
36 tan 25 = BC
16.78707569 = BC
But we know that he is 5.5 ft tall so the flagpole is 5.5 ft taller than BC
The triangle is from his eyes to the pole
Add 5.5 to BC to find
the height of the flagpole is BC +5.5
16.787 +5.5
22.28707569
To the nearest tenth
The flagpole is 22.3 ft
Answer/Step-by-step explanation:
Recall the acronym SOHCAHTOA. This is what we would apply as appropriate in each case.
8. θ = 40°
Opp = m
Adj = 20
Thus, apply TOA
Tan (θ) = opp/adj
Plug in the values
Tan (40) = m/20 (equation)
20×Tan(40) = m
m = 16.7820
9. θ = 22°
Hyp = w
Adj = 18
Thus, apply CAH
Cos (θ) = adj/hyp
Plug in the values
Cos 22 = 18/w (equation)
w×cos 22 = 18
w = 18/(cos 22)
w = 19.4136
10. θ = 35°
Hyp = 55
Opp = x
Thus, apply SOH
Sin θ = opp/hyp
Plug in the values
Sin 35 = x/55 (equation)
55×sin 35 = x
x = 31.5467
11. θ = 33°
Hyp = 19
Adj = x
Thus, apply CAH
Cos θ = adj/hyp
Plug in the values
Cos 33 = x/19 (equation)
19×cos 33 = x
x = 15.9347
12. θ = 17°
Opp = 7
Hyp = x
Thus, apply SOH
Sin θ = opp/hyp
Plug in the values
Sin 17 = 7/x (equation)
x×sin 17 = 7
x = 7/(sin 17)
x = 23.9421
13. θ = 40°
Opp = 15
Adj = x
Thus, apply TOA
Tan θ = opp/adj
Plug in the values
Tan 40 = 15/x (equation)
x×Tan 40 = 15
x = 15/(Tan 40)
x = 17.8763
Answer:
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X + 3.2 = -3.5
x = -3.5 - 3.2 = -6.7
Answer:
Both versions of the expression equal the exact same amount;one is just much shorter.Simplifying algebraic expressions is the same idea,except you have variables in your expression.So,Basically you're turning a long expression into something you can easily make sense of