Answer:
examples of non-statistical questions are: how old are you?
Step-by-step explanation:
Non-Statistical Questions. The next type of question is the non-statistical question. This is the type of question that only has one answer. This one answer also doesn't change. You don't need to gather several points of data to answer the question.
Hi,
Answer:
k = 
Step-by-step explanation:
Subtract 4k from both sides
6k - 4k = 2k
2k - 8 = 15
Add 8 on both sides (you want to get rid of the 8 in order to leave the k alone)
2k = 23
k = 23/2
Have a good day!
Answer:
3
=
6
h
M
Step-by-step explanation:
4
=
2
h
⋅
(
1
M
)⋅
3
=
6
h
M
you answered one of my questions before now i answer yours lol.
The slope is 7/5 and the equation of the line is 5y - 7x = 0 if the points (10,14) and (35,49) form a proportional relationship.
<h3>What is the slope?</h3>
The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

From the above formula, we can find the slope of the line:
m = (49-14)/(35-10)
m = 35/25
m = 7/5
The equation will be:
y = 7x/5 + c
here c is the y-intercept
Plug (10, 14) in the equation to find the value of c
14 = 7(10)/5 + c
c = 0
y = 7x/5 or
5y - 7x = 0
Thus, the slope is 7/5 and the equation of the line is 5y - 7x = 0 if the points (10,14) and (35,49) form a proportional relationship.
Learn more about the slope here:
brainly.com/question/3605446
#SPJ1
Exponentail thingies
easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0
now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero
5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1
5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4
x=log₅1 and/or log₅4
second quesiton
same thing
1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero
2^x-8=9
2^x=8
x=3
2^x-2=0
2^x=2
x=1
x=3 or 1
first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3