Answer:
as a decimal is 1.735.
Step-by-step explanation:
To convert a fraction into a decimal, you first have to put the fraction into simplest form.
1. Simplest form
To do this you must find a number you can equally divide both numbers by.
That number in this situation, 5.
Now you must make this simplest formed fraction into a mixed number.
2. Simplest form into Mixed number
To do this you see how many times the denominator, the bottom number of the fraction, goes into the numerator, the upper part of the fraction.
Since 200 x 2 = 400 and since 400 > 347 this means...
200 goes into 347, once.
Finally, subtract and divide.
Remember put the whole number in front of the mixed number, before the decimal
3. Subtract, divide, decimalize
Hopes this helps you!
Have a good afternoon!
Step-by-step explanation:
I think the typing of the answer options must have some typos.
the magnitude of a vector is the length of the vector.
the length of the vector is Pythagoras over its coordinates.
this vector goes from (3, -6) to (-4, 1), so the relative vector coordinates are -4 - 3 and 1 - -6 = -7, 7.
so the magnitude of length of the vector is
sqrt((-7)² + 7²) = sqrt(49+49) = sqrt(98)
= 9.899494937...
the direction angle is the angle of the vector with the x-axis.
it is the inverse tan of y/x. and in this case in the second (upper left) quadrant, since the vector is pointing up and left.
the inverse tan of 7/-7 = inverse tab of 1/-1 =
inverse tan of -1 in the second quadrant is 135°.
For
(a-b)(a+b)=a^2-b^2
x^2-y^2-14x+49
x^2-14x+49-y^2
(x-7)^2-y^2
(x-7-y)(x-7+y)
or
(x-y-7)(x+y-7)
Answer:
Step-by-step explanation:
First thing is to remember the sin ratio. It is, by definition, the side opposite over the hypotenuse of the reference angle. In QIII the side opposite the angle is -8 which is one of the legs of a right triangle, and the hypotenuse, which is always positive, is 10. That means that if we are going to find the cosine of the angle, we need the other leg of the triangle. Using Pythagorean's Theorem, we find that
and
and
so
a = 6. But because we are QIII, that value is negative, because x is negative in QIII.
That leg happens to be the side adjacent to the angle. The cosine of the angle is the side adjacent over the hypotenuse. So now that we have the side adjacent as -6, we can say that the cosine of the angle is -6/10.
The height of the antenna on the roof of the local building is approximately 8 meters.
The situation forms a right angle triangle.
<h3>Properties of a right angle triangle:</h3>
- One of its angles is equals to 90 degrees
- The sides of the triangles can be calculated using Pythagoras theorem.
Therefore, let's find the height of the building and the radio antenna from the eye point.
Using trigonometric ratios,
tan 40° = opposite / adjacent
tan 40° = x / 25
where
x = the height of the building and the radio antenna from the eye point.
x = 25 tan 40
x = 25 × 0.83909963117
x = 20.9774907794 meters
Let's find the height of the building from his eye point.
tan 28° = y / 25
where
y = height of the building from his eye point
y = 25 × tan 28°
y = 25 × 0.53170943166
y = 13.2927357915 meters
Height of the antenna = 20.9774907794 - 13.2927357915 = 7.68475498786
Height of the antenna ≈ 8 meters
learn more on elevation here: brainly.com/question/17582385?referrer=searchResults
