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3 years ago

One characteristic of all linear functions is that they change by

Mathematics

2 answers:

BabaBlast [244]3 years ago

8 0

I think its number 4 but also 3

slavikrds [6]3 years ago

4 0

Answer by YourHope:

Hi uwu

One characteristic of all linear functions is that they change by..?

3) equal differences over equal intervals!

ﾍ(=￣∇￣)ﾉ

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Combine like terms to create an equivalent expression.<br><br> 17−3(37n−27)71 −3( 73 n− 72)

patriot [66]

Answer:

$\frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})=1-\frac{9}{7}n$

Step-by-step explanation:

Given : Expression $\frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})$

To find : Combine like terms to create an equivalent expression ?

Solution :

Step 1 - Write the expression,

$\frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})$

Step 2 - Apply distributive property, $a(b+c)=ab+ac$

$=\frac{1}{7}-3\times \frac{3}{7}n+3\times \frac{2}{7}$

$=\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}$

Step 3 - Combine like terms,

$=\frac{1}{7}+\frac{6}{7}-\frac{9}{7}n$

$=\frac{1+6}{7}-\frac{9}{7}n$

$=\frac{7}{7}-\frac{9}{7}n$

$=1-\frac{9}{7}n$

Therefore, $\frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})=1-\frac{9}{7}n$

4 0

3 years ago

Read 2 more answers

What are the zeros of this function?

Irina-Kira [14]

Answer:

D. x=4 and x=6 (A P E X)

8 0

2 years ago

One teacher wants to give each student two and 1/6 slices of pizza if the teachers had 13 slices of pizza how many students will

hram777 [196]

Answer:

6 students.

Step-by-step explanation:

First let's combine 2 and 1/6.

6/6 + 6/6 + 1/6 = 13/6.

Now we will turn 13 to 13/1 and divide by 13/6

$\frac{13}{1} \div \frac{13}{6} = \frac{13}{1} \times \frac{6}{13}$

$\frac{13 \: \times \: 6 \: = \: 78}{ 1 \times \: 13 \: = \: 13}$

$78 \div 13 = 6$

So, the teacher will hand the pizza out to 6 students.

5 0

2 years ago

Write the number in 2 other forms 7.632 (Please Help. ) :)

expeople1 [14]

I think you mean a different way it can be written.
7.632 can be written as a
—>mixed number<— 7 and 79/125
Or
As a —>percentage<— it is 763.2%
Or
As a —> simplistic fraction<— it is 954/125

Hopefully this helps...

4 0

3 years ago

Read 2 more answers

Determine whether the integral is convergent or divergent. [infinity] 7 e−1/x x2 dx convergent divergent Changed: Your submitted

inessss [21]

I suppose the integral could be

$\displaystyle\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx$

In that case, since $-\frac1x\to0$ as $x\to\infty$ , we know $e^{-1/x}\to1$ . We also have $\left(e^{-1/x}\right)'=\frac{e^{-1/x}}{x^2}>0$ , so the integral is approach +1 from below. This tells us that, by comparison,

$\displaystyle\frac{e^{-1/x}}{x^2}\le\frac1{x^2}\implies\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx\le\int_7^\infty\frac{\mathrm dx}{x^2}$

and the latter integral is convergent, so this integral must converge.

To find its value, let $u=-\frac1x$ , so that $\mathrm du=\frac{\mathrm dx}{x^2}$ . Then the integral is equal to

$\displaystyle\int_{-1/7}^0e^u\,\mathrm du=e^0-e^{-1/7}=1-\frac1{\sqrt[7]{e}}$

4 0

3 years ago