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Alik [6]
3 years ago
9

A free-body diagram represents forces acting on a system.

Physics
2 answers:
kirill115 [55]3 years ago
8 0
It would be false !!!!!!!!!!
Georgia [21]3 years ago
7 0

Answer:

False because free-body diagram is a sketch of only the object in question and the forces acting upon it, to scale.

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Just a test for my internet :)
Talja [164]

Answer:

Okay

Explanation:

3 0
2 years ago
The reason a charged balloon will stick to a wall is that?
kari74 [83]
The negative charges of the balloon will stick to the positive charges on the wall.
6 0
3 years ago
Which part of and organism is preserved in cast and mold fossils
Lubov Fominskaja [6]

Answer:

bones

Explanation:

Bones are is preserved in cast and mold fossils.

Normally the other 'parts of the body' like muscles, ligaments, blood and organs are soft.

5 0
3 years ago
The problem of perception is best characterized as
kicyunya [14]

Answer:

The definition is defined in the clarification section down, and according to the particular circumstance.

Explanation:

  • The trouble with perception is that even though we generally perceive it if delusions and hallucinations become conceivable, therefore perception is unlikely.
  • The perception seems to be our issue: adapting to this culture requires giving up some vocabulary and ideas that are in the path of only possessing or taking up valuable space.
8 0
3 years ago
"The International Space Station (ISS) orbits at a distance of 350 km above the surface of the Earth. (a) Determine the gravitat
vagabundo [1.1K]

Answer:

(a) g = 8.82158145m/s^2.

(b) 7699.990192m/s.

(c)5484.3301s = 1.5234 hours.(extremely fast).

Explanation:

(a) Strength of gravitational field 'g' by definition is

g = \frac{M_{(earth)} }{r^2} G , here G is Gravitational Constant, and r is distance from center of earth, all the values will remain same except r which will be radius of earth + altitude at which ISS is in orbit.

r = 6721,000 meters, putting this value in above equation gives g = 8.82158145m/s^2.

(b) We have to essentially calculate centripetal acceleration that equals new 'g'.

a_{centripetal}=\frac{V^2}{r} =g here g is known, r is known and v is unknown.

plugging in r and g in above and solving for unknown gives V = 7699.990192m/s.

(c)  S = vT,  here T is time period or time required to complete one full revolution.

S =  earth's circumfrence , V is calculated in (B) T is unknown.

solving for unknown gives T = 5484.3301s = 1.5234hours.

3 0
3 years ago
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