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AleksandrR [38]
3 years ago
15

The problem of perception is best characterized as

Physics
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

The definition is defined in the clarification section down, and according to the particular circumstance.

Explanation:

  • The trouble with perception is that even though we generally perceive it if delusions and hallucinations become conceivable, therefore perception is unlikely.
  • The perception seems to be our issue: adapting to this culture requires giving up some vocabulary and ideas that are in the path of only possessing or taking up valuable space.
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Problem 7:__deletededc326999bef85931fda5d1ab0d68e21218f27b46f4f11ab80872358251b584ddeleted__ 0N86-C1-52-40-A837-22820 If object
laila [671]

Answer:

the kinetic energy of body B is twice the kinetic energy of body A

Explanation:

The kinetic energy of a body is given by

          K = ½ m v²

If two objects leave the same point, suppose that at the same height when they reach the ground they have the same velocity.

Therefore if the mass of body b is twice the mass of body A

          m_{b} = 2 m_{a}

         K_{b} = ½ (2 m_{a}) v²

          K_{b} = 2 (½ m_{a} v²)

          K_{b} = 2 K_{a}

therefore the kinetic energy of body B is twice the kinetic energy of body A

3 0
3 years ago
How do you calculate the work done when lifting an object?
vichka [17]
Mass x Gravity x Height
5 0
3 years ago
Suppose the gravitational force between two spheres is 30 N. If the magnitude of both masses doubles, and the distance between t
mixer [17]

Answer:

60 N

Explanation:

because when we double the 30N, we will get 60N as a force

8 0
2 years ago
A 4 kg object moving to the left collides with and sticks to a 3 kg object moving to the right. Which of the following is true o
madam [21]

Answer:

D. The motion cannot be determined without knowing the speeds of the objects before the collision.

Explanation:

This question is tricky! We know the object moving to the left has a greater mass than the one moving to the right. We'd <em>assume</em> they would move to the left because the leftwards object has a greater mass, right?

Not. So. Fast.

We can solve for the objects' final velocity using the formula for momentum, m₁v₁ + m₂v₂ = (m₁ + m₂)v .

Now here's where the trap is sprung: <em>we don't think about the equation</em>. This shows that the final velocity of the objects and the direction depends on both the mass of the objects <em>and</em> their initial velocity.

Basically, what if the 3 kg object is moving at 1 m/s and the 4 kg object is moving at –0.5 m/s? The objects would move to the <em>right</em> after the collision!

Do we know the velocity of these objects? No, right?

That means we <em>can't</em> determine the direction of their motion <u>unless we know their initial, pre-collision velocity</u>. This question is tricky because we look at the 4 kg vs. 3 kg and automatically assume the 4 kg object would dictate the direction of motion. That's not true. It depends on velocity as well.

I hope this helps you! Have a great day!

4 0
3 years ago
At the outer edge of a rotating space habitat, 130 m from the center, the rotational acceleration is g. What is the rotational a
enyata [817]

Answer:

Explanation:

Given:

R1 = 130 m

R2 = 65 m

w^2R = g

Assume, g = 9.81 m/s^2

w^2 = 9.81/130

w = 0.275 rad/s

At R2 = 65 m

g = w^2R

= (0.275^2) × 65

= 4.905 m/s^2

In conclusion,

g × R = k

g1/R1 = g2/R2

g2 = (g1 × 65)/130

= g1 ×1/2

= g1/2

6 0
3 years ago
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