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3 years ago

14

in a lab, a block weighing 80 n is attached to a spring scale, and both are pulled to the right on a horizontal surface, as show

n above. friction between the block and the surface is negligible. what is the acceleration of the block when the scale reads 32 n?

1 answer:

shutvik [7]3 years ago

6 0

Answer:

4.0 m/s ^2

Explanation:

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A car travels 554 miles south in 10.4 hours . what is the velocity of the car ? show all steps

kirill115 [55]

Answer:

<h3>The answer is 53.27 mi/hr</h3>

Explanation:

To find the velocity covered by the car we use the formula

$v = \frac{d}{t} \\$

where

d is the distance

t is the time

From the question

d = 554 miles

t = 10.4 hrs

We have

$d = \frac{554}{10.4} \\ = 53.2692307...$

We have the final answer as

<h3>53.27 mi/hr</h3>

Hope this helps you

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4 years ago

Estimate the volume of each ball. Use the formula

Mila [183]

The given question is incomplete. The complete question is:

Estimate the volume of each ball. Use the formula $v=\frac{4\pi\times r^3}{3}$ where v is the volume and r is the radius. record the volume in table A of your student guide. The radius of the tennis ball is 2.1 cm and the radius of thr golf ball is 2.0 cm. What is the estimated volume of the table tennis ball in $cm^3
$ What is the estimated volume of the golf ball in

Answer: Volume of the tennis ball is $38.8cm^3$ and Volume of the golf ball is $33.5cm^3$

Explanation:

We have to find the Volume of tennis ball and golf ball by using the formula $v=\frac{4\pi\times r^3}{3}$

Radius of the tennis ball = 2.1 cm

Radius of the golf ball =2.0 cm.

Putting the value of radius in the formula , we get:

Volume of the tennis ball = $\frac{4\times 3.14\times (2.1cm)^3}{3}
=38.8cm^3$

Volume of the golf ball = $\frac{4\times 3.14\times (2.0cm)^3}{3}
=33.5cm^3$

Volume of the tennis ball is $38.8cm^3$ and Volume of the golf ball is $33.5cm^3$

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The correct answer is a -80 J

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