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Rzqust [24]
3 years ago
6

Investigator Robbins is called to the scene of a robbery. The officer on the scene thinks that the suspect entered the home from

the garage. As Investigator Robbins checks over the house, he does not find any evidence of forced entry. He cannot find any physical evidence near the garage door at all. There is a window open above the kitchen sink and footprints in the mud under the window outside. Based on his examination, what conclusion might Investigator Robbins make?
1. The officer was correct; the garage was the point of entry.

2. There is no evidence to indicate that anyone entered the home.

3. The officer's conclusion was mistaken, and a suspect may have entered through the window.

4. The garage was the point of entry, but the window was the escape route.
Physics
1 answer:
ICE Princess25 [194]3 years ago
8 0

Answer:

3

Explanation:

Since the evidence found points to the window on investigation remember there was a foot print below the window as well as the window been opened.

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What is the wavenumber of the stretching vibrational mode for the CO molecule, given that the force constant of the bond is 680
Gnesinka [82]

Answer:

1.10134 * 10⁻⁹m⁻¹

Explanation:

K = 680Nm⁻¹

μ = ?

μ = (m₁ + m₂) / m₁m₂

compound = CO

C = 12.0 g/mol = 0.012kg/mol

O = 16.0g/mol = 0.016kg/mol

μ = (m₁ + m₂) / m₁m₂

μ = (0.012 + 0.016) / (0.012*0.016) = 145.83

v = 1/2πc * √(k/μ)

ν = 1/ 2*3.142* 3.0*10⁸ * √(630/145.83)

v = 5.30*10⁻¹⁰ * 2.078

v = 1.10134*10⁻⁹m⁻¹

8 0
3 years ago
A=100m/s2<br> Vi=10m/s<br> T=10sec<br> Vf?
IrinaK [193]

Answer:

v=u+at

v= 10+100×10

v = 10+1000

v = 1010 m/s

3 0
2 years ago
When a moving car is brought to a stop with the brakes, its acceleration vector is 29. (a) in the same direction as its velocity
professor190 [17]

To develop this problem we will apply the concepts related to the kinematic equations of motion, specifically that of acceleration. Acceleration can be defined as the change of speed in an instant of time, mathematically this is

\vec{a} = \frac{\vec{v_2}-\vec{v_1}}{\Delta t}

If a mobile is decreasing its speed (it is slowing down), then its acceleration is in the opposite direction to the movement. This would imply that the acceleration vector is opposite to the velocity vector.

Therefore the correct answer is B.

7 0
3 years ago
The critical angle for total internal reflection occurs when:___________.
Anastaziya [24]

Answer:

b) the refracted ray has an angle of 90 degrees

Explanation:

The angle of incidence is measured with respect to the normal separation of the media. The critical angle for total internal reflection occurs is:

\theta=arcsin(\frac{n_2}{n_1})

Here n_2 and n_1 are the refractive index of the mediums. This equation is an application of Snell's law, for the case where  the refracted ray has an angle of 90^\circ.

5 0
2 years ago
A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the mo
Svetllana [295]

Answer:

The gravitational potential energy of the nickel at the top of the monument is 8.29 J.

Explanation:

We can find the gravitational potential energy using the following  formula.

GPE=mgh

Identifying given information.

The nickel has a mass m=0.005 \,kg, and it is a the top of Washington Monument.

The Washington Monument has a height of h=555 \, ft, thus we need to find the equivalence in meters using unit conversion in  order to find the gravitational potential energy.

Converting from feet to meters.

Using the conversion factor 1 m = 3.28 ft, we have

h = 555 \, ft \times \cfrac{1 \, m}{3.28 \, ft}

That give u s

h = 169.2 \, m

Finding Gravitational Potential Energy.

We can replace the height and mass on the formula

GPE=mgh

And we get

GPE=(0.005)(9.8)(169.2) \, J

\boxed{GPE=8.29 \,J}

The gravitational potential energy of the nickel at the top of the monument is 8.29 J.

7 0
3 years ago
Read 2 more answers
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