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Ipatiy [6.2K]
3 years ago
9

Estimate the volume of each ball. Use the formula

Physics
2 answers:
Mila [183]3 years ago
6 0

The given question is incomplete. The complete question is:

Estimate the volume of each ball. Use the formula v=\frac{4\pi\times r^3}{3} where v is the volume and r is the radius. record the volume in table A of your student guide. The radius of the tennis ball is 2.1 cm and the radius of thr golf ball is 2.0 cm. What is the estimated volume of the table tennis ball in cm^3
 What is the estimated volume of the golf ball in

Answer: Volume of the tennis ball is 38.8cm^3 and  Volume of the golf ball is 33.5cm^3

Explanation:

We have to find the Volume of tennis ball and golf ball by using the formula v=\frac{4\pi\times r^3}{3}

Radius of the tennis ball = 2.1 cm

Radius  of the golf ball =2.0 cm.

Putting the value of radius in the formula , we get:

Volume of the tennis ball =  \frac{4\times 3.14\times (2.1cm)^3}{3}
=38.8cm^3

Volume of the golf ball =   \frac{4\times 3.14\times (2.0cm)^3}{3}
=33.5cm^3

Volume of the tennis ball is 38.8cm^3 and  Volume of the golf ball is 33.5cm^3

astraxan [27]3 years ago
4 0

it's  38.8 and 33.5 hope this helps

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A friend insists that electric current is the same as electrical energy. Work with a partner to develop a rebuttal
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Answer: The electrons flowing through the wire are referred to as a quantity of electricity, and the flow of electricity is referred to as “an electric current.”

Explanation: Hope it Helps have a blessed day

4 0
3 years ago
An engineering firm is designing a ski lift. The wire rope needs to travel with a linear velocity of 2.0 meters per second, and
Mazyrski [523]

Answer:

The diameter of the bull-wheel is 3.82

Explanation:

Given that,

Velocity = 2.0 m/s

Angular velocity = 10 rev/m

\omega=10\times\dfrac{2\pi}{60}

\omega=1.0472\ rad/s

We need to calculate the diameter of bull-wheel

Using formula of angular velocity

v= r\omega

r=\dfrac{v}{\omega}

Put the value into the formula

r=\dfrac{2.0}{1.0472}

r=1.91\ m

The diameter of the bull-wheel

D=2r

D=2\times1.91

D=3.82\ m

Hence, The diameter of the bull-wheel is 3.82 m.

6 0
3 years ago
A 0.700-kg ball is on the end of a rope that is 2.30 m in length. The ball and rope are attached to a pole and the entire appara
otez555 [7]

Answer:

The tangential speed of the ball is 11.213 m/s

Explanation:

The radius is equal:

r=2.3*sin70=2.161m (ball rotates in a circle)

If the system is in equilibrium, the tension is:

Tcos70=mg\\Tsin70=\frac{mv^{2} }{r}

Replacing:

\frac{mg}{cos70} sin70=\frac{mv^{2} }{r} \\Clearing-v:\\v=\sqrt{rgtan70}

Replacing:

v=\sqrt{2.161x^{2}*9.8*tan70 } =11.213m/s

7 0
3 years ago
Electrolytes are considered ________ when placed in a solution and allow for adequate conduction of ________ charges.
DedPeter [7]

Answer:

Electrolytes are considered ions when placed in a solution and allow for adequate conduction of particle charges.

Explanation:

Electrolytes are substances that, when are dissolved in solution, separates into electrical positive charges (cations) and electrical negative charges (anions) which are known as ions.

These ions have an adequate capacity to conduct particle charges and, therefore electricity.

Sodium, calcium, phosphate and potassium, are examples of electrolytes.  

<u>Hence, the correct answer is:</u>

Electrolytes are considered ions when placed in a solution and allow for adequate conduction of particle charges.

I hope it helps you!

3 0
4 years ago
A 3.20 kg block starts at rest and slides a distance d down a frictionless β = 30.0 ◦ incline, where it runs into a spring with
Virty [35]

Answer:

Explanation:

a ) work done by gravitational force

= mg sinθ ( d + .21)

Potential energy stored in compressed spring

= 1/2 k x²

= .5 x 431 x ( .21 )²

= 9.5

According to conservation of energy

mg sinθ ( d + .21)  = 9.5

3.2 x 9.8 x sin 30( d + .21 ) = 9.5

d = 40 cm

b )

As long as mg sin30 is greater than kx ( restoring force ) , there will be acceleration in the block.

mg sin30 = kx

3.2 x 9.8 x .5 = 431 x

x =  3.63 cm

When there is compression of 3.63 cm in the spring , block will have maximum velocity. there after its speed will start decreasing.

7 0
3 years ago
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