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exis [7]
3 years ago
5

Round 0.25 to the nearest hundredth ​

Mathematics
2 answers:
Elza [17]3 years ago
7 0

Answer:

Step-by-step explanation: 0.26

Elenna [48]3 years ago
3 0

Answer:

0.25

Step-by-step explanation:

there is no hundredth in 0.25

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5x2 +14x = 3<br> How do you complete the square
katovenus [111]
If I’m correct negative one half
5 0
4 years ago
Use the relationship between the
motikmotik

The equation x° = 180° - (37°+ 53°) can be used to find the value of x.

Step-by-step explanation:

Step 1; There are three lines in the given diagram. There are a baseline and two other lines. Out of the other two lines, one extends above and below the baseline whereas the other extends only above. Since the baseline is horizontal and the others are at angles we have the sum of all the three angles as 180° i.e. 37°, x°, and 53°.

37° + x° + 53° = 180°.

Step 2; To solve the value of x, we keep the unknown value at the left-hand side whereas all the known values are taken to the right side of the equation.

x° = 180° - (37°+ 53°).

So the fifth option can be used to determine the value of x.

4 0
4 years ago
If 2a - 8 = 4 and 3b - 8 = 10, what is the value of a + b?
barxatty [35]
A+B=22 is your answer
7 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
4 years ago
Can someone help me with this
zmey [24]

Answer:

No, because they look like they are different sizes. Or you could say the first answer

3 0
3 years ago
Read 2 more answers
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