Answer:
Step-by-step explanation:
From the given information:
The null and the alternative hypothesis can be well written as:


Given that:
n = 200
x = 135
Alpha ∝ = 0.05 level of significance
Then;
⇒ 
= 200 × 0.6 × (1 -0.6)
= 200 × 0.6 × 0.4
= 48 ≥ 10
The sample proportion 

= 0.675
The test statistics 


Z = 2.165
The P-value = P(Z > 2.165)
= 1 - P(Z < 2.165)
From the z tables
= 1 - 0.9848
= 0.0152
Reject the null hypothesis since P-Value is lesser than alpha. ( i.e. 0.0152 < 0.05).
Thus, there is enough evidence to conclude that the value of the population proportion is greater than 0.6
Step-by-step explanation:
y−x2+2x=−4y-x2+2x=-4 , y+x=2
<span>B.When x=-4, y=-9 and when x=2, y=3.
</span><span>3y-6x=-3
3(-9) - 6(-4)= -3
-27 +24 =-3
-3 = -3
</span>
<span>3y-6x=-3
3(3) -6 (2) = -3
9 - 12 = -3
-3 = -3
</span>
5.6 x 2.1 x 6.6 = 77.616 2 significant figures would be 78 cm³ 2 decimal places would be 77.62 cm³
P=2(9-15) is what i got first i simplify 1/2p to p/2, then subtract from both sides, multply both sides by 2, then regroup terms, and last switch sides