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3 years ago

Khalid carried water bottles to the field to share with his team at halftime. The water bottles weighed

Mathematics

1 answer:

jeka57 [31]3 years ago

4 0

Answer:

<u>Answer</u><u>:</u><u> </u><u>D</u>

${50x}^{2} + 30x + 10$

• first factorise out 10:

$= 10(5 {x}^{2} + 3x + 1)$

• then find factors of the quadratic equation in the bracket:

You might be interested in

What is 1 ft^3 to m^3

cluponka [151]

Answer:

1 ft3= 0,028 m3

Step-by-step explanation:

We know that a 1 ft= 0,305 m,

if we cubed the above equation we have the following

1 ft3= (0,305)^3 m3

1 ft3= 0,028 m3

5 0

3 years ago

Organize the given volumes of cubes as either a perfect cube or not-perfect cube.

stiks02 [169]

Answer:

343m3,8m3,1000m3 for Perfect squares

300m3,9m3,900m3 for Not-perfect squares

Step-by-step explanation:

Did an assignment on edge

4 0

3 years ago

Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4

dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

$x_1\ =\ -2$

$y_1\ =\ 3$

$z_1\ =\ -4$

Distance is measure across the line

$\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}$

So, we can write

$\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k$

$=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k$

$=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k$

$=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}$

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

$3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3$

$=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18$

$=>18k-24+12k+9+10k-32\ =\ 18$

$=>\ k\ =\dfrac{13}{8}$

So,

$x\ =\ 3k-4$

$=\ 3\times \dfrac{13}{8}-4$

$=\ \dfrac{7}{4}$

$y\ =\ \dfrac{4k+3}{2}$

$=\ \dfrac{4\times \dfrac{13}{8}+3}{2}$

$=\ \dfrac{19}{4}$

$z\ =\ \dfrac{5k-16}{3}$

$=\ \dfrac{5\times \dfrac{13}{8}-16}{3}$

$=\ \dfrac{-21}{8}$

Now, the distance of point from the plane is given by,

$d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}$

$=\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}$

$=\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}$

$=\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}$

$=\ \sqrt{\dfrac{1177}{64}}$

$=\ 4.28$

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

= 8.56 unit

So, the distance of a point from it's image is 8.56 units.

4 0

3 years ago

A farmer finds there is a linear relationship between the number of bean stalks, nn, she plants and the yield, yy, each plant pr

Alex

The linear relationship in the form y = y = 3n + 72

What is linear relationship?

In statistics, a straight line of correlation between two variables is referred to as a linear relationship (or linear association). The mathematical equation y = mx + b can be used to represent linear relationships graphically.

<h3>According to the given information :</h3>

Each plant generates 34 oz of beans when she plants 30 stalks, and 33 stalks results in 33 oz of beans per plant, according to the information we have provided.

Equation 1 using data 1:

y = mn + b

Equation 1 using data 1:

30 = 34m + b

Equation 2 using data 2:

33 = 33m + b

Subtract equation 1 from equation 2:

33 - 30 = 34m + b - 33m - b

3 = m

m = 3

Rearrange equation 1 to solve for b:

b = 34(3) - 30

b = 102 - 30

b = 72

Therefore the equation becomes:

y = 3n + 72

The linear relationship in the form y = y = 3n + 72

To know more about linear relationship visit:

brainly.com/question/28158670

#SPJ4

5 0

2 years ago

Which of the following is the sum of the polynomials 5x2 - 4x + 1 and -3x2 + x - 3 ?

yulyashka [42]

The answer is 2x^2-3x-2.
Just align the polynomials and combine like terms.

3 0

3 years ago