Harini has twice as many sweet as Dora. After eating 18 sweets each she has 5 times as much as Dora. How many sweets did Harini start with?
1 answer:
9514 1404 393
Answer:
48
Step-by-step explanation:
Let d represent the number of sweets Dora has to start with. Then 2d is the number Harini had. After they each ate 18, the ratio of their numbers is ...
(2d -18)/(d -18) = 5/1
2d -18 = 5(d -18) . . . . . multiply by d-18
72 = 3d . . . . . . . . . . subtract 2d-90
24 = d . . . . . . . . . divide by 3
2d = 48
Harini started with 48 sweets .
You might be interested in
Answer:
y+4=6(x+7)
Step-by-step explanation:
y-y1=m(x-x1)
y-(-4)=6(x-(-7))
y+4=6(x+7)
Answer:
3.33333333333333333333333333333
Step-by-step explanation:
4.5 * 3.33333333333333333 = 14.999999999999 but round and it = 15
The answer should be 149.668992
Answer:
11 books
b=(58+8)/6
Step-by-step explanation:
58+8=66
66/6=11
11
Answer:
x <u>></u> 15
Step-by-step explanation:
4(x + 15) <u>></u> 120
Divide by 4
x + 15 <u>></u> 30
Subtract 15
x <u>></u> 15