This sine function has the form y = f(x) = a sin (bx + c), where |a| is the amplitude, b is the frequency, and c determines the phase shift.
The period of this sine curve is 2 pi/b, or (in this problem) 2 pi/(1/2).
The phase shift of this curve is -c/b, or -(pi/4)/(1/2). Simplify this.
The amplitude is |-3|, or just 3.
Draw a set of coordinate axes. Draw light horizontal lines through y=3 and y=-3. These are the max and min. values of this sine function.
Plot the phase shift on your x-axis.
Your sine function will begin at (phase shift value, 0) and continue for one period. Add the period to the phase shift value. Draw a sine curve beginning and ending at these two x-values.
I encourage you to share your calculations and to sketch the graph described here. Then I could give you more specific feedback on your work. Good luck!
Answer:
Answer is below
Step-by-step explanation:
The y-values are all real numbers because they reach every possible y-value from -∞ to ∞ on the y-axis.
Answer:
D.
Step-by-step explanation:
IF cos(x)=0.4226 then 
⇒ x=65° so Compl. x = (90° - x) = 25⁰, finally sin (25⁰) = 0.4226
