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alina1380 [7]
3 years ago
15

Harini has twice as many sweet as Dora. After eating 18 sweets each she has 5 times as much as Dora. How many sweets did Harini

start with?
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0

9514 1404 393

Answer:

  48

Step-by-step explanation:

Let d represent the number of sweets Dora has to start with. Then 2d is the number Harini had. After they each ate 18, the ratio of their numbers is ...

  (2d -18)/(d -18) = 5/1

  2d -18 = 5(d -18) . . . . . multiply by d-18

  72 = 3d . . . . . . . . . . subtract 2d-90

  24 = d . . . . . . . . . divide by 3

  2d = 48

Harini started with 48 sweets.

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