On comparing values , we see that student which has the largest percent error is <u>A. Student 4: 9.61 m/s2
.</u>
<u>Explanation:</u>
Here, we have Four students measured the acceleration of gravity. The accepted value for their location is 9.78m/s2. Let's calculate which student’s measurement has the largest percent error :
<u>A. Student 4: 9.61 m/s2
</u>
Percentage of error = %.
<u>B. Student 3: 9.88 m/s2
</u>
Percentage of error = %.
<u>C. Student 2: 9.79 m/s2
</u>
Percentage of error = % .
<u>D. Student 1: 9.78 m/s2</u>
Percentage of error = % .
On comparing values , we see that student which has the largest percent error is <u>A. Student 4: 9.61 m/s2
.</u>
Answer:
distance between object and image = 18.9 cm
Explanation:
given data
radius of curvature = 18 cm
focal length = 1/2 radius of curvature
magnification = 40%
to find out
distance between object and image
solution
we know lens formula that is
1/f = 1/v + 1/u ....................1
here f = 18 /2 and v and u is object and image distance
and we know m = 40% = 0.40
so 0.40 = -v / u
so here v = - 0.40 u
so from equation 1
1/f = 1/v + 1/u
2/18 = - 1/0.40u + 1/u
u = -13.5 cm ..................2
and
v = -0.40 (- 13.5)
v = 5.4 cm ......................3
so from equation 2 and 3
distance between object and image = 5.4 + 13.5
distance between object and image = 18.9 cm
Answer:
On average a galaxy has, between <u>800 billion and 3.2 trillion planets.</u>