For this problem, you would use the equation v=u+at. In this case, u=1 v=0 (when the object is at rest) a=-1
v=u+at
0=1+(-1)t
t=1 second
Heat rises, and it is warmer at the equator, so I think warm air would rise at the equator and move towards the cooler poles.
Second hand:
1 rev per minute = (2π radians/minute) x (1 min/60sec) = π/30 rad/sec
Minute hand:
1 rev per hour = (2π radians/hour) x (1 hr/3600 sec) = π/1800 rad/sec
Hour hand:
1 rev per 12 hours = (2π rad/12 hr) x (1 hr/3600 sec) = π/21,600 rad/sec
As long as the clock is in good working order, and the hands are turning steadily at their normal rate, there is no angular acceleration.
Answer:
Acceleration is a vector quantity which is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.
