Número de 4 dígitos divisible entre 5 y 9

Write the equation of a line that contains (2,−2) and perpendicular to another line with slope −1. (20 POINTS)

Kay [80]

Y=mx+b or -2=-1 x 2+b, b= -2(-1)(2) b=0

Therefore the equation of the line is

y=-1x

8 0

2 years ago

why write a quadratic function whose graph has the given characteristics vertex :(2,3) point on graph (0,-1)

GaryK [48]

<h3>Answer:</h3>

f(x) = -(x -2)² +3

<h3>Step-by-step explanation:</h3>

We can fill in the vertex (h, k) values immediately in the vertex form ...

... f(x) = a(x -h)² +k

To find the value of a, we solve the equation for a at some point other than the vertex. The given point is (0, -1), so we can use that:

... -1 = a(0 -2)² +3

... -4 = 4a . . . . . . . . . subtract 3, simplify

... -1 = a . . . . . . . . . . . divide by 4

Now, we know the function is ...

... f(x) = -(x -2)² +3

5 0

3 years ago

What is 3/5(15k+10)=12k-9 in steps

Diano4ka-milaya [45]

<em>multiply both sides by 5 </em> 3(15k+10)=5(12k-9)
<em>get rid of the brackets</em> 45k+30=60k-45
<em>take away 45k to both sides</em>   30=15k-45
<em>plus 45 to both sides</em>   75=15k
<em>divide both by 15</em> k=5

8 0

3 years ago

Paid for $22 for for movie tickets how many would they have pay for for 16 tickets

bija089 [108]

Answer:

$352

Step-by-step explanation:

One ticket costs $22, so 16 tickets would be 22 times 16.

Final Answer: $352

5 0

2 years ago

Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +

GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3) ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2) ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)

On solving above equation for x

(x+6) (x+3) =2(x+3) (2x+2)

x+6 = 4x + 4

x-4x = 4 – 6

x = $\frac{2}{3}$

Dimension of pool A

Length = x+6 = ( $\frac{2}{3}$ ) +6 = 6.667m

Width = x +3 = ( $\frac{2}{3}$ ) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2( $\frac{2}{3}$ ) + 6 = $\frac{22}{3}$ = 7.333m

Width = 2x + 2 = 2( $\frac{2}{3}$ ) + 2 = $\frac{10}{3}$ = 3.333m

Verifying the area:

Area of pool A = ( $\frac{20}{3}$ ) x ( $\frac{11}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Area of pool B = ( $\frac{22}{3}$ ) x ( $\frac{10}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0

3 years ago