Answer:
finding the number of equal-sized parts into which a number can be split
Step-by-step explanation:
Let us split the number 80 into 10 equal parts.
80 = 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8
= 8 + 8 + 8 +...to 10 times
= 8(10)
or 
So, if N is any number and p is one of its equal part, then the number of parts into which N is split by p is 
.
Hence, finding the number of equal-sized parts is best modeled with a division expression.
CF = CD + DF (since D is simply a point on the line, and C to that point added onto F to that point is CF), so 4y-9+2y-7=14. Adding it up, we get 6y-16=14 and adding by 16 we get 30=6y. Dividing both sides by 6, we get y=5. Plugging that into DF, we get 10-7=DF=3
61/100, because if it is 0.(value) than it is value / 100 assuming value is 2 digits long. We cannot simplify it further because 61 is prime number.
Answer:
See below.
Step-by-step explanation:
From the given info the 2 triangles are isosceles with AE = FR and ET = RP because the 2 sets of base angles are equal.
As the base angles are congruent m < E = m < R.
So the are 2 triangles are congruent by SAS, ASA and AAS.
Yes-this is because you can start from the 7th part and then go backwards to forwards to find the letter/number/pattern you need
