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mojhsa [17]
2 years ago
13

A gardener will use up to 220 square feet for planting flowers and vegetables. She wants the area used for vegetables to be at l

east twice the area used for flowers. Let x denote the area (in square feet) used for flowers. Let y denote the area (in square feet) used for vegetables. Shade the region corresponding to all values of x and y that satisfy these requirements.
Mathematics
1 answer:
geniusboy [140]2 years ago
7 0
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Evaluate the following expressions if a = 2, b = 3, x = 4, and y = 5.<br> b^2+3(2x-y)
butalik [34]

Hi there! Hopefully this helps!

-------------------------------------------------------------------------------------------------------

<h2 /><h2>Answer: 18</h2><h2>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h2><h2 />

First we need to substitute the value of the variable into the expression.

b^{2}+3(2x-y) = 3^{2} + 3 (2(4)-5) .

Now we need to solve 3^{2} + 3 (2(4)-5).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

3^{2} + 3 (2(4)-5)

First, calculate 3 to the power of 2 and get 9.

9+3(2\times 4-5)=18

Multiply 2 and 4 to get 8.

9+3(8-5) =18  

Subtract 5 from 8 to get 3.    

9+3\times 3 =18  

Multiply 3 and 3 to get 9.

9+9 =18.

<h2>And the answer is, you guessed it, 18!</h2>

7 0
2 years ago
"In the figure, what is m<br> A) 15<br> B) 35<br> C) 50<br> D) 65"
laila [671]
B) 35
the formula is .5(outer angle - inner angle) = .5(100-30)=.5*70=35
7 0
2 years ago
Read 2 more answers
You already know its another giveaway
nasty-shy [4]

Answer: yay thxs

Step-by-step explanation:

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2 years ago
If I got a 28% on a test and my grade is an 88% he would that affect my grade?
OlgaM077 [116]
If its from one test it doesnt always affect your grades but if you are continuously getting 28% then it will badly affect your grades
7 0
3 years ago
Read 2 more answers
Part 1) You deposit $100 in a bank account that earns 5% interest, compounded monthly.
insens350 [35]
1) A=100(1+0.05/12)^12t
2) 125=100(1+0.05/12)^12t
125/100=(1+0.05/12)^12t
Log(125/100)=12t*log(1+0.05/12)
12t=log(125÷100)÷log(1+0.05÷12)
t=[log(125÷100)÷log(1+0.05÷12)]/12
T=4.5 years
8 0
3 years ago
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