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mojhsa [17]
3 years ago
13

A gardener will use up to 220 square feet for planting flowers and vegetables. She wants the area used for vegetables to be at l

east twice the area used for flowers. Let x denote the area (in square feet) used for flowers. Let y denote the area (in square feet) used for vegetables. Shade the region corresponding to all values of x and y that satisfy these requirements.
Mathematics
1 answer:
geniusboy [140]3 years ago
7 0
Hshahgsuzhshgdshhshsjushsgsgsjhdgdhdhhhgghvfdf
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Ivan has 15 yards of green felt and 12 yards of blue felt to make 3 quilts if Ivan uses the same total number of yards for each
mixas84 [53]

Answer:

9 yards

Step-by-step explanation:

Let the length of each quilt be 'l'.

Given:

Length of green felt (g) = 15 yards

Length of blue felt (b) = 12 yards

Total number of quilts = 3

Now, the length of 3 quilts is given as:

Total\ length=l+l+l=3l ----- (1)

As per question:

Total length = Length of green felt + Length of blue felt

Total length = g+b

Total\ length=15+12=27--------- (2)

Now, comparing equations (1) and (2), we get:

3l=27\\\\l=\frac{27}{3}\\\\l=9\ yards

Hence, each quilt measures 9 yards in length.

3 0
3 years ago
William went shopping for a new phone because of a sale. The store was offering a 15% discount. If the price on the tag was $41,
Alik [6]

Answer:

*WILLIAM AFTON*

Real Answer:

38 dollars and 11 cents.

3 0
3 years ago
Problems with Equations: Mastery Test
GaryK [48]

Step-by-step explanation:

The answer is 8

Because you have to put each value of x given in the equation 3x = 24

So when you put the value 8

3(8) = 24

24 = 24

6 0
4 years ago
Derivative of tan(2x+3) using first principle
kodGreya [7K]
f(x)=\tan(2x+3)

The derivative is given by the limit

f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h

You have

\displaystyle\lim_{h\to0}\frac{\tan(2(x+h)+3)-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan((2x+3)+2h)-\tan(2x+3)}h

Use the angle sum identity for tangent. I don't remember it off the top of my head, but I do remember the ones for (co)sine.

\tan(a+b)=\dfrac{\sin(a+b)}{\cos(a+b)}=\dfrac{\sin a\cos b+\cos a\sin b}{\cos a\cos b-\sin a\sin b}=\dfrac{\tan a+\tan b}{1-\tan a\tan b}

By this identity, you have

\tan((2x+3)+2h)=\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}

So in the limit you get

\displaystyle\lim_{h\to0}\frac{\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan(2x+3)+\tan2h-\tan(2x+3)(1-\tan(2x+3)\tan2h)}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h+\tan^2(2x+3)\tan2h}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h}h\times\lim_{h\to0}\frac{1+\tan^2(2x+3)}{1-\tan(2x+3)\tan2h}
\displaystyle\frac12\lim_{h\to0}\frac1{\cos2h}\times\lim_{h\to0}\frac{\sin2h}{2h}\times\lim_{h\to0}\frac{\sec^2(2x+3)}{1-\tan(2x+3)\tan2h}

The first two limits are both 1, and the single term in the last limit approaches 0 as h\to0, so you're left with

f'(x)=\dfrac12\sec^2(2x+3)

which agrees with the result you get from applying the chain rule.
7 0
3 years ago
Mr. Soto plans to open a savings account. Four banks offer the annual interest rates shown. Which list shows these interest rate
Delvig [45]
Ok, so IDK if I'm about to do this problem right, but here we go;


so first, lets change these all to decimals (I more of a decimal gal)

3 1/2 = 3.5
3 2/3 = 3.6666 (repeating)
3 3/5 = 3.6
3 3/8 = 3.375

So now, just order them from greatest to least.  

3.66666, 3.6, 3.5, 3.375.  

Now, change them back to fractions.  
3 2/3, 3 3/5, 3 1/2, 3 3/8


So, if I'm correct, the answer is 3 2/3%, 3 3/5%, 3 1/2%, 3 3/8%
Hopefully I solved your problem! 
6 0
3 years ago
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