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Arada [10]
3 years ago
10

More massive objects have a large gravitational force or weight. Why do heavier objects accelerate to the ground at the same rat

e as lighter ones? A) Smaller objects have more inertia. B) More massive objects have less inertia. C) All objects have the same pull of gravity on them. D) Heavier objects need a greater force to accelerate according to F=ma.
Physics
2 answers:
8090 [49]3 years ago
5 0

Answer:

D) Heavier objects need a greater force to accelerate according to F=ma.

Explanation:

The force of gravity acting on an object is equal to:

F = mg

where m is the mass of the object and g is the acceleration due to gravity. According to the formula, heavier objects (objects with greater mass, m) have a larger force of gravity acting on them.

However, the acceleration of an object towards the ground is given by:

a=\frac{F}{m}

therefore, we see that if the object is heavier (larger mass, m), the force of gravity (F) must also be larger in order to have the same acceleration a.

Volgvan3 years ago
3 0

Is DD. Heavier objects need a greater force to accelerate accoirding to f ma.

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A thin, metallic spherical shell of radius 0.227 m has a total charge of 6.03 × 10 − 6 C placed on it.
KATRIN_1 [288]

Answer:

Explanation:

Given

radius r=0.227 m

Charge on surface Q=6.03\times 10^{-6} C

Point Charge inside sphere q=1.15\times 10^{-6} C

Electric Field at r=0.735 m

Treating Surface charge as Point charge and applying Gauss law

E_{total}A=\frac{q_{enclosed}}{\epsilon _0}

where A=surface area up to distance r

E_{total}=\frac{Q+q}{4\pi r^2}

E_{total}=\frac{6.03\times 10^{-6}+1.15\times 10^{-6}}{4\pi (0.735)^2\times 8.85\times 10^{-12}}

E_{total}=1.194\times 10^{5} N/C

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3 years ago
How much do you have to increase the vertical distance to double the impact speed of an object?
sergey [27]
Twice the distance to double an impact
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If an astronaut goes on a space walk outside the Space Station, she will quickly float away from the station unless she has a te
Strike441 [17]

Answer:

d. This statement is false. She and the Space Station share the same orbit and will stay together unless they are pushed apart.

Explanation:

In astronomy, orbit is simply a path of an object around another object in a space. That is, orbit is a path of a body that revolves around a gravitating center of mass. Examples of an orbit is are satellite around a planet, orbit around a center of galaxy, planet around the sun, and among others.

On the other hand, space station refers to a spacecraft that can support a group of human for long time in the orbit. Another names for space stations are orbital space station and orbital station.

Therefore, an astronaut goes on a space walk outside the Space Station shares the same orbit with the space station and they will stay together unless they are pushed apart.

4 0
3 years ago
Which law states that for any closed loop, the sum of the length segments times the magnetic field in the direction of the segme
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3 0
3 years ago
Read 2 more answers
I.Solve the following problems and answer the following questions. Show all your work and provide answers rounded off to the app
Ilia_Sergeevich [38]

The sprinter’s average acceleration is 1.98 m/s²

The given parameters;

  • initial velocity of the sprinter, u = 18 km/h
  • final velocity of the sprinter, v = 27 km/h
  • time of motion of the sprinter, t = 3.5 x 10⁻⁴ h

Convert the velocity of the sprinter to m/s;

initial \ velocity, u = 18 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 5 \ m/s\\\\final \ velocity, v =27 \frac{km}{h} \times \frac{1000 \ m}{1 \ km} \times \frac{1 \ h}{3600 \ s} = 7.5 \ m/s\\\\

The time of motion is seconds;

t = 3.5 \times 10^{-4} \ h \times \frac{3600 \ s}{1 \ h} = 1.26 \ s

The sprinter’s average acceleration is calculated as follows;

a = \frac{v- u}{t} \\\\a = \frac{7.5 \ m/s \ - \ 5 \ m/s}{1.26 \ s} \\\\a = 1.98 \ m/s^2

Thus, the sprinter’s average acceleration is 1.98 m/s²

Learn more here:brainly.com/question/17280180

6 0
3 years ago
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