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aksik [14]
4 years ago
13

A spaceship is moving past us at a speed close to the speed of light. If we could measure the mass of the spaceship as it goes b

y, what would it be?
Physics
1 answer:
lidiya [134]4 years ago
3 0

Answer:

the mass of the space ship would be greater than its mass when at rest, it's mass becomes so high that it reaches infinity.

Explanation:

From Einstein's relativity equation E=mC^{2}, where E is energy, m is mass and C is the speed of light, the equation shows that energy (E) and mass (m) are interchangeable because there are different forms of the same thing if mass is somehow converted into energy (just as in the atomic bomb). This equation shows that mass increases with speed (as an object moves, its mass increases), and if an object were to move close to the speed of light (the fastest speed a particle can move in a vacuum) its mass would increase that in reaches infinity.

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A microphone receiving a pure sound tone feeds an oscilloscope, producing a wave on its screen. If the sound intensity is origin
Temka [501]

Answer:

The new intensity = 3.38 × 10⁻⁵ W/m²

Explanation:  

Intensity of sound wave:

The intensity of sound  is the rate of flow of flow of energy, per unit area, perpendicular to the direction of the sound wave.

Intensity (I) ∝ A²

where I = intensity, A = Amplitude.

∴ I₁/I₂ = A₁²/A²₂............................... equation 1

From the question, the amplitude increase by 30% of the initial

∴ A₂ = A₁ + 0.3A₁ = 1.3A₁, I₁ = 2.00×10⁻⁵ W/m²

∴ (2.00×10⁻⁵)/I₂ = A₁²/(1.3A₁)²

(2.00×10⁻⁵)/I₂ = 1/1.3²

 making I₂ the subject of the equation

I₂ = (2.00 × 10⁻⁵)×1.3² = 3.38 × 10⁻⁵ W/m₂

The new intensity = 3.38 × 10⁻⁵ W/m²

7 0
4 years ago
Two ponies of equal mass are initially at diametrically opposite points on the rim of a large horizontal turntable that is turni
AleksandrR [38]

Answer:A

Explanation:

Given

Two ponies are at Extreme end of turntable with mass m

suppose turntable is moving with angular velocity \omega

Moment of inertia of Turntable and two ponies

I=I_o+2mr_0^2

let say at any time t they are at a distance of r from center such r

Moment of inertia at that instant

I'=I_0+2mr'^2

I'

conserving angular momentum as net Torque is zero

I\omega =I'\omega '

\omega '=\frac{I}{I'}\times \omega

\omega '>\omega

Thus we can say that angular velocity increases as they move towards each other.        

3 0
3 years ago
How does friction make it possible for you to walk across the floor?
Tema [17]

if we are walking on a perfectly smooth ground which has no friction our force would simply cancel out the force reverted by the ground and we would fall.

We need it to help push out feet off the ground

Hope those helps :)

5 0
3 years ago
A stone is thrown horizontally from 2.4m above the ground at 35m/s. The wall is 14m away and 1m high.At what height the stone wi
KIM [24]

The stone reaches the wall at a height of <u>1.62 m</u>.

The stone lands at a point <u>24.5 m</u> from the point of projection.

The stone is projected horizontally with a velocity u at a height <em>h</em> from the ground. The wall is located at a distance <em>x</em> from the point of projection. The stone takes a time <em>t</em> to reach the wall and in the same time the stone falls a vertical distance <em>y</em>.

The horizontal distance <em>x</em> is traveled with a constant velocity <em>u</em>.

x=ut

Calculate the time taken <em>t</em>.

t=\frac{x}{u} \\ =\frac{14m}{35 m/s} \\ =0.40s

The stone's initial vertical velocity is zero. It falls through a distance <em>y</em> in the time <em>t</em> under the action of acceleration due to gravity <em>g</em>.

y=\frac{1}{2} gt^2\\ \frac{1}{2} (9.81m/s^2)(0.40s)^2\\ =0.784m

The height  <em>h₁ </em>of the stone above the ground when it reaches the wall  is given by,

h_1=h-y\\ =(2.4m)-(0.784m)\\ =1.616m=1.62m

When the stone reaches the wall, its height from the ground is <u>1.62m.</u>

The stone thus crosses over the wall, since the height of the wall is 1 m. It reaches the ground at a distance <em>R</em> from the point of projection. If the time taken by the stone to reach the ground is <em>t₁, </em>then,

h=\frac{1}{2} gt_1^2

Calculate the time taken by the stone to reach the ground.

t_1=\sqrt{\frac{2h}{g} } \\=\sqrt{\frac{2(2.4m)}{9.81m/s^2} } \\ =0.699 s

The horizontal distance traveled by the stone is given by,

R=ut_1 \\ =(35m/s)(0.699s)\\ =24.5m

The stone lands at point 24.5 m from the point of projection and 10.5 m from the wall.

3 0
3 years ago
A coulomb is a measure of what? PLEASE ANSWER NOW I AM IN AN END OF YEAR PHYSICS EXAM PLEAAASE
just olya [345]

Explanation:

it measures electric charge

8 0
3 years ago
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