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aksik [14]
3 years ago
13

A spaceship is moving past us at a speed close to the speed of light. If we could measure the mass of the spaceship as it goes b

y, what would it be?
Physics
1 answer:
lidiya [134]3 years ago
3 0

Answer:

the mass of the space ship would be greater than its mass when at rest, it's mass becomes so high that it reaches infinity.

Explanation:

From Einstein's relativity equation E=mC^{2}, where E is energy, m is mass and C is the speed of light, the equation shows that energy (E) and mass (m) are interchangeable because there are different forms of the same thing if mass is somehow converted into energy (just as in the atomic bomb). This equation shows that mass increases with speed (as an object moves, its mass increases), and if an object were to move close to the speed of light (the fastest speed a particle can move in a vacuum) its mass would increase that in reaches infinity.

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Multiple-Concept Example 6 reveiws the principles that play a role in this problem. A nuclear power reactor generates 2.3 x 109
r-ruslan [8.4K]

Answer:

change in mass = 2.41*10^{8}kg

Explanation:

The change in the mass can be computed by using the relation

E=\Delta mc^2\\\Delta m=\frac{E}{c^2}(1)

That is, the energy liberated comes from the mass of the nuclear fuel. The energy generated in one year is

E=Pt=2.3*10^{9}\frac{J}{s}*1 year*\frac{365.25 day}{1 year}*\frac{24h}{1 day}*\frac{3600s}{1h}=7.25*10^{16}J

Hence, by replacing in the equation (1) you have  (c=3*10^{8}m/s)

\Delta m=\frac{7.25*10^{16}J}{3*10^{8}\frac{m}{s}}=2.41*10^{8}kg

HOPE THIS HELPS!!

3 0
3 years ago
Read 2 more answers
An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane travel
Licemer1 [7]

Answer:

v=4.44\frac{m}{s}

Explanation:

Given that the airplane starts from the rest (this is initial velocity equals to zero)  and accelerates at a constant rate, position can be described like this: x=v_{0}t +\frac{1}{2} at^{2} where x is the position, t is the time a is the acceleration and v_{0} is initial velocity. In this way acceleration can be found. a=\frac{2(x-v_{0}t) }{t^{2} } =\frac{2(1.11m-0)}{1s^{2} } =2.22\frac{m}{s^{2} }.

Now we are able to found velocity at any time with the formula: v=v_{0} +at = 0\frac{m}{s} +(2.22\frac{m}{s^{2}}.2s)=4.44\frac{m}{s}

3 0
3 years ago
During the period that the moon’s phases are changing from new to full, the moon is _____. waxing exhibiting retrograde motion w
Sindrei [870]
The answer that best fits the blank is the term WAXING. The moon is waxing whenever it reaches to the period that its phases are transitioning from new to full. The answer is the first option. This is when it is more that half is illuminated. Hope this helps.
3 0
3 years ago
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Please help answer much as possible there's 4 questions
katovenus [111]

Answer:

6. A

7. A

9. B

hope dis helps ^-^

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3 years ago
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While filming an intense action sequence for the next James Bond movie, a controlled explosion detonates 1.1 km away from the ac
kolezko [41]

Answer:

The time that will pass between the feeling and hearing the explosion is 2,86 secs

Explanation:

First, let's calculate the time that the wave takes to travel until the actors feel the explosion:

1,1 km*\frac{1.000 mts}{1 km} *\frac{sec}{3.000 mts} = 0,37 secs

Now, the time that pass while the actors hear the sound is:

<em>(Remember that the sound speed in the air is 340 m/s on average)</em>

1,1 km * \frac{1.000 mts}{1 km} * \frac{sec}{340 mts} = 3,23 secs

So, the time between the feeling and hearing is 3,23 - 0,37 = 2,86 secs

4 0
3 years ago
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