1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aksik [14]
3 years ago
13

A spaceship is moving past us at a speed close to the speed of light. If we could measure the mass of the spaceship as it goes b

y, what would it be?
Physics
1 answer:
lidiya [134]3 years ago
3 0

Answer:

the mass of the space ship would be greater than its mass when at rest, it's mass becomes so high that it reaches infinity.

Explanation:

From Einstein's relativity equation E=mC^{2}, where E is energy, m is mass and C is the speed of light, the equation shows that energy (E) and mass (m) are interchangeable because there are different forms of the same thing if mass is somehow converted into energy (just as in the atomic bomb). This equation shows that mass increases with speed (as an object moves, its mass increases), and if an object were to move close to the speed of light (the fastest speed a particle can move in a vacuum) its mass would increase that in reaches infinity.

You might be interested in
If the moon were twice as far from years as it is now the following would be true
zubka84 [21]
The question is incomplete.

The distance between the Moon and Earth influences: 1) the attractive gravitational force between them, 2) the tides, 3) the eclipses, 4) the period of each full turn of the moon around the Earth.

Assuming the question refers to the gravitational attraction, we must use the fact that, as per, Newton's Universal Gravitaional Law, the attractive force between the two bodies is inversely related to the square distance that separates them.

Then, if the Moon were twice as far, the gravitational pull would be one fourth (1/4) of actual pull.

7 0
3 years ago
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.0 m/s. Th
elena55 [62]

<u>Answer:</u>

<em>Thunderbird is 995.157 meters behind the Mercedes</em>

<u>Explanation:</u>

It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird  decided to take a pit stop and slows down for 250 m. She spent 5 seconds  in the pit stop.

Here final velocity v=0 \ m/s

initial velocity u= 71 m/s  distance  

Distance covered in the slowing down phase = 250 m

v^2-u^2=2as

a= \frac {(v^2-u^2)}{2s}

a = \frac {(0^2-71^2)}{(2 \times 250)}=-10.082 \ m/s^2

v=u+at

t= \frac {(v-u)}{a}

= \frac {(0-71)}{(-10.082)}=7.042 s

t_1=7.042 s

The car is in the pit stop for 5s t_2=5 s

After restart it accelerates for 350 m to reach the earlier velocity 71 m/s

a= \frac {(v^2-u^2)}{(2\times s)} = \frac{(71^2-0^2)}{(2 \times 370)} =6.81 \ m/s^2

v=u+at

t= \frac{(v-u)}{a}

t= \frac{(71-0)}{6.81}= 10.425 s

t_3=10.425 s

total time= t_1 +t_2+t_3=7.042+5+10.425=22.467 s

Distance covered by the Mercedes Benz during this time is given by s=vt=71 \times 22.467= 1595.157 m

Distance covered by the Thunderbird during this time=250+350=600 m

Difference between distance covered by the Mercedes  and Thunderbird

= 1595.157-600=995.157 m

Thus the Mercedes is 995.157 m ahead of the Thunderbird.

6 0
3 years ago
There are two possibilities for final stage of extremely massive stars. The first is a
makkiz [27]

Answer: Black hole.

Explanation:

As the massive star "compacts" under its own gravity, it triggers a massive supernova, after this point the remains of the star can become a neutron star, which is a very compact star made primarily, as the name says, of neutrons. The other possibility is a black hole, which is a finite region of space wherein it's interior there is a big concentration of mass, which creates a gravitational field strong enough that there is no particle that can escape it.

3 0
3 years ago
Write any two different between work and power?​
attashe74 [19]

Answer:

1. Work Is a type of Physical Activity  

2. Power is Basically Having control of Society

Explanation:

3 0
3 years ago
Read 2 more answers
Consider the graph below that represents the variation of the velocity with respect to time of an object moving along the x - ax
vazorg [7]

In a velocity-time graph, the area under the curve represents the distance.

The distance traveled from 10s to 18 s is

\begin{gathered} d\text{ = }\frac{1}{2}\times10\times(18-10) \\ =\text{ 40 m} \end{gathered}

Final Answer: The distance traveled is 40 m from time 10 s to 18 s.

3 0
1 year ago
Other questions:
  • A crowbar makes our work easier by multiplying effort true or false​
    10·1 answer
  • Which of these is most likely a characteristic of a parent isotope before it releases radioactive particles?
    11·1 answer
  • a 1.05 kg water bottle is sitting on the teacher's desk it is .20 m tall and has a radius of .03 m find the force that the water
    8·1 answer
  • The velocity of in water is 1500 m/s.
    5·1 answer
  • You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 275 N in the positive x di
    12·1 answer
  • ⚠️I need help with the last question!⚠️
    11·1 answer
  • Latitude and longitude picture.​
    15·1 answer
  • A box has a mass of 6.0 kg. What is its weight on the mars, where the acceleration due to
    8·1 answer
  • Help me with this please :)
    7·2 answers
  • A 290-turn solenoid having a length of 32 cm and a diameter of 11 cm carries a current of 0.30 A. Calculate the magnitude of the
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!