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Answer:
a)1.51*10^-22joules b) 1.89*10^-7m
Explanation:
Work done to stop the proton = the kinetic energy of the proton = 1/2 mv^2 = 1/2* 1.67*10^-27* 425*425 = 1.51* 10 ^ -22 joules
b) net force acting to stop the proton = 8.01*10^-16
Work done needed to stop the proton = net force acting opposite the motion * distance
Distance covered = need work done/ net force
Distance = 1.51*10^-22/8.01*10^-16= 1.89*10^-7m
To solve this problem it is necessary to apply the concepts related to electromotive force or induced voltage.
By definition we know that the induced emf in the loop is equal to the negative of the change in the magnetic field, that is,
Where A is the area of the loop, B the magnetic field and t the time.
Replacing with our values we have that
Therefore the thermal energy produced is given by
The thermal energy produced in the loop is
Answer:
The mass of the block m is:
Explanation:
Let's analyze the block by parts
For the block M
(1)
Where:
- T is the tension
- W(x) is the component of the weight in the x-direction
- F(f) is the friction force
For the block m
(2)
Now, let's combines equation (1) and (2):
Finally, let's solve it for block m.
I hope it helps you!