1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sergio [31]
3 years ago
11

A miler covers one mile in training at a 6 minute pace ( 4 laps on a 1/4 mile track ). What is his speed in mph. And in metric u

nits of m/s?
Physics
1 answer:
SVETLANKA909090 [29]3 years ago
7 0
The answer to the problem is<span>4.246 m/sec^2</span>
You might be interested in
Describe using examples how objects can be at rest and in motion simultaneously
elena-14-01-66 [18.8K]
An object can be at rest and still be in motion because the earth is always in motion.

5 0
3 years ago
What is the magnitude of the force a charge 25uc exerts on a charge 3mc 35 cm away?
Misha Larkins [42]
5.51 × 10 power 12 newton is answer
3 0
3 years ago
Jake calculates that the frequency of a wave is 230 hertz, and its wave is moving at 460 m/s. What is the wavelength of the wave
Nesterboy [21]

Wavelength = (speed) / (frequency) = (460 m/s) / (230/sec) = <em>2 meters</em>


3 0
3 years ago
A block of 250-mm length and 54 × 40-mm cross section is to support a centric compressive load P. The material to be used is a b
musickatia [10]

Answer:

P = 17.28*10⁶ N

Explanation:

Given

L = 250 mm = 0.25 m

a = 0.54 m

b = 0.40 m

E = 95 GPa = 95*10⁹ Pa

σmax = 80 MPa = 80*10⁶ Pa

ΔL = 0.12%*L = 0.0012*0.25 m = 3*10⁻⁴ m

We get A as follows:

A = a*b = (0.54 m)*(0.40 m) = 0.216 m²

then, we apply the formula

ΔL = P*L/(A*E)  ⇒ P = ΔL*A*E/L

⇒  P = (3*10⁻⁴ m)*(0.216 m²)*(95*10⁹ Pa)/(0.25 m)

⇒  P = 24624000  N = 24.624*10⁶ N

Now we can use the equation

σ = P/A

⇒  σ = (24624000  N)/(0.216 m²) = 114000000 Pa = 114 MPa > 80 MPa

So σ > σmax  we use σmax

⇒  P = σmax*A = (80*10⁶ Pa)*(0.216 m²) = 17280000 N = 17.28*10⁶ N

7 0
3 years ago
Which graph illustrates constant speed and velocity?
boyakko [2]

The correct graph is <u>D</u>.

The graph <em>A</em> is a straight line sloping downwards and it shows that the speed of the body is decreasing at a constant rate. Therefore, this s a graph of a body that is under a constant deceleration.

The graph B is a straight line which slopes upwards. Hence the graph shows that the speed of the body increases at a constant rate. Therefore, this is a graph of a body that is accelerating at a constant rate.

The graph C is curved line, which curves upwards. The slope of the curve increases with time. This is therefore, a graph of a body which is under increasing acceleration.

The graph D, however is a straight line parallel to the time axis. The speed of the body has the same value at all times. Therefore, Graph D is the graph which shows the motion of a body with constant speed.

8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the name for all the electromagnetic waves that exist
    9·1 answer
  • Does visible light make up a relatively large part or a relatively small part of the electromagnetic spectrum?
    7·1 answer
  • Which type of thermal energy transfer does a wrapping of cotton or plastic reduce the most, conduction, convection, radiation, t
    14·1 answer
  • If you see a lightning stroke and then, 15 seconds later, hear the thunder, the lightning is about ____ miles away
    13·1 answer
  • In what medium does sound travel fastest​
    11·1 answer
  • A train traveled 85 mph for 7 hours how far did it travel?
    12·2 answers
  • 15. A car travelling towards the right has a mass of 1332 kg and has a speed of 25 m/s. A truck is
    15·1 answer
  • Which of the following does light demonstrate?
    15·2 answers
  • Where does a body have more weight the poor at the eqator of the earth.​
    5·2 answers
  • Suppose the gravitational force between two spheres is 30 N. If the magnitude of both masses doubles, and the distance between t
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!