Ask question

Ask question

All categories

2 years ago

11

According to Charles’s law, when the temperature of a gas increases at constant pressure its a. volume increases. b. mass increa

ses. c. volume decreases. d. particles move more slowly.

1 answer:

xxMikexx [17]2 years ago

8 0

The answer is A, the volume increases.
hope this helps

You might be interested in

Gravitational forces is ------ force

mel-nik [20]

Answer:

Gravitational force is <u>noncontact</u> force

Explanation:

Contact force occurs due to the contact between two different objects. Non-contact force occurs due to either attraction or repulsion between two objects such that there is no contact between these objects. There is no field linked with the contact force. ... Gravitational force is an example of a non-contact force.

7 0

2 years ago

Which device is using a motor? A. A water heater creates heat energy from electric energy. B. A waterfall rotates a waterwheel t

Mumz [18]

Answer:

C is the right answer.

Body massager uses electrical energy to move back and forth. In this sense, a motor is being used for the operation

4 0

3 years ago

What did you learn from organize Notes, write 2 to 3 paragraphs explaining how that process is designed to help with your learni

Setler79 [48]

Answer:

yo ni siquiera he leido Organizar Notes y quisiera responderte pero el sistema no me deja escribir bien se esta alocando

Explanation:

5 0

3 years ago

3. In order to follow proper golf etiquette there should be no more than

jarptica [38.1K]

In order to follow proper golf equipment there should be no more than 4️⃣ players in your party

so, the answer is 4

8 0

2 years ago

If a steel cylindrical specimen is stressed nominally to 53 MPa, what stress level exists at the tip of an elliptical surface fl

ElenaW [278]

Answer:

227.9MPa

Explanation:

Length of the flaws is given by

2b = 5.8microns

b = 2.9 × 10⁻⁶m

The relation between the radius of curvature and length and width of the elliptical flaw

$r = \frac{a^2}{b}$

$a = \sqrt{rb}$

Equation for stress at the tip of an elliptical surface flaw

$\sigma _t = \sigma(1 + 2\frac{b}{a} )\\\\\sigma _t = \sigma(1 + 2\frac{b}{\sqrt{rb} })\\\\\sigma _t = \sigma(1 + 2\frac{\sqrt{b} }{\sqrt{r} })\\\\\sigma _t = \sigma(1 + 2\sqrt{\frac{b}{r} })$

$\sigma _t = 53 \times 10^6 (1 + 2\sqrt{\frac{2.9\times10^-^6 }{1065 \times 10^-^9} } \\\\\sigma _t = 227.9 \times 10^6\\\\\sigma _t = 227.9MPa$

4 0

3 years ago