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3 years ago

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According to Charles’s law, when the temperature of a gas increases at constant pressure its a. volume increases. b. mass increa

ses. c. volume decreases. d. particles move more slowly.

1 answer:

xxMikexx [17]3 years ago

8 0

The answer is A, the volume increases.
hope this helps

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The hypotenuse of an isosceles right triangle is 36 units. to the nearest tenth, what is the length of one of the legs

GarryVolchara [31]

The length of one of them would be 6

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3 years ago

A net force of 200 newtons is applied to a wagon for 3 seconds. This cause the wagons to undergo a change in momentum of ?

suter [353]

Physics- damon, Monday, December 1, 2014 at 3:27 pm force =change in momentum\ change in time or m a if m is constant

change in momentum/3=200

change in momentum =3*200 kg m/s

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3 years ago

Vector vector a has a magnitude of 29 units and points in the positive y-direction. when vector vector b is added to vector a ,

Nutka1998 [239]

Good morning.

We have:

$\mathsf{\overset{\to}{a} = 29\overset{\to}{j}}$

Where j is the unitary vector in the direction of the y-axis.

We have that

$\mathsf{\overset{\to}{a}+\overset{\to}{b} = -18\overset{\to}{j}}$

We add the vector -a to both sides:

$\mathsf{\overset{\to}{b} = -18\overset{\to}{j} -\overset{\to}{a} = -18\overset{\to}{j} -29\overset{\to}{j}}\\ \\ \mathsf{\overset{\to}{b}=-47\overset{\to}{j}}$

Therefore, the magnitude of b is 47 units.

5 0

3 years ago

Read 2 more answers

When a 70 kg man sits on the stool, by what percent does the length of the legs decrease? Assume, for simplicity, that the stool

allochka39001 [22]

The diameter of one leg of the stool is missing and it's 2cm.

Answer:

(ΔL/L) = 0.00729%

Explanation:

If the Weight of the man is W, the weight will be distributed equally on the 3 legs and so the reactions for each leg will be W/3 or F/3.

Now, Youngs modulus(Y) of douglas fir wood is about 1.3 x 10^(10) N/m^2. Gotten from youngs modulus of common materials.

Now, weight of man is 70kg.

Now diameter of one leg is 2cm.so radius of one leg = 2/2 = 1cm = 1 x 10^(-2)m

Area for one leg is; π( 1 x 10^(-2)m)^2 = 3.14 x 10^(-4)m

Now as stated earlier, the force on one leg is; F/3.

Now F = mg = 70 x 9.81 = 686.7N

So, force on one leg = 686.7/3 = 228. 9N

Now we know youngs modulus(Y) = Stress/Strain.

Stress = F/A while Strain = ΔL/L

Therefore Y = (F/A) / (ΔL/L)

And therefore, (ΔL/L) = F/(AY)

So (ΔL/L) = 228.9/(3.14 x 10^(-4))x(1.3 x 10^(10)) = 7. 29 x 10^(-5)

When expressed in percentage, it becomes 0.00729%

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3 years ago

As a mass on a spring moves farther from the equilibrium position, how do the velocity, acceleration, and force change

Umnica [9.8K]

Refer to the diagram shown below.

m = the mass of the object
x = the distance of the object from the equilibrium position at time t.
v = the velocity of the object at time t
a = the acceleration of the object at time t
A = the amplitude ( the maximum distance) of the mass from the equilibrium
position

The oscillatory motion of the object (without damping) is given by
x(t) = A sin(ωt)
where
ω = the circular frequency of the motion
T = the period of the motion so that ω = (2π)/T

The velocity and acceleration are respectively
v(t) = ωA cos(ωt)
a(t) = -ω²A sin(ωt)

In the equilibrium position,
x is zero;
v is maximum;
a is zero.

At the farthest distance (A) from the equilibrium position,
x is maximum;
v is zero;
a is zero.

In the graphs shown, it is assumed (for illustrative purposes) that
A = 1 and T = 1.

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3 years ago