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NemiM [27]
3 years ago
10

Brainers, please help me please

Mathematics
1 answer:
ra1l [238]3 years ago
4 0

Answer:

W = 12

L = 16

Step-by-step explanation:

Givens

L = L

W = 1/2 L + 4

Perimeter = 56

Formula

2L + 2W = Perimeter

Solution

Sustitute

2L + 2(1/2L + 4) = 56

2L + L + 8 = 56

3L + 8 = 56

3L + 8 - 8 = 56 - 8

3L = 48

3L/3 = 48/3

L = 16

W = 1/2 L + 4

W = 8 + 4

W = 12

Check

2L + 2W = 56

2*16 + 2*12 = 56

32 + 24 = 56

56 = 56 and it checks.

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What is the answer to this
IRINA_888 [86]

Answer:  3

Step-by-step explanation:

y-3=2(x+1)

y - 3 = 2x + 2

 +3.        +3

y=2x+5

-1 is the x value so plug it in where the x is in the equation

y=2(-1) +5

y= -2 + 5

y= 3

5 0
2 years ago
William has 24 cans of fruit and 60 cans of vegetables that he will be putting into bags for a food drive. He wants each bag to
nataly862011 [7]

Answer:

See explanation

Step-by-step explanation:

William has 24 cans of fruit and 60 cans of vegetables that he will be putting into bags for a food drive.

Factor number 24 and 60:

24=2\cdot 12=2\cdot 2\cdot 6=2\cdot 2\cdot 2\cdot 3=2^3\cdot 3\\ \\60=2\cdot 30=2\cdot 2\cdot 15=2\cdot 2\cdot 3\cdot 5=2^2\cdot 3\cdot 5

Find the greatest common factor

GCF(24,60)=2^2\cdot 3=12

Hence, the greatest number of bags William can make is 12.

Each of these bags will have 24\div 12=2 cans of fruit and 60\div 12=5 cans of vegetables.

If he made fewer bags, 6 bags, each of these bags will have 24\div 6=4 cans of fruit and 60\div 6=10 cans of vegetables.

If he made fewer bags, 4 bags, each of these bags will have 24\div 4=6 cans of fruit and 60\div 4=15 cans of vegetables.

If he made fewer bags, 3 bags, each of these bags will have 24\div 3=8 cans of fruit and 60\div 3=20 cans of vegetables.

If he made fewer bags, 2 bags, each of these bags will have 24\div 2=12 cans of fruit and 60\div 2=30 cans of vegetables.

7 0
2 years ago
Plss help me with this do not add any links or they will be reported and plss do not answer just for the points thank you!!!!!!
Sonbull [250]

Answer:

x=-4/3+y/3. y=-11/4+3x/4

Tap to view steps...

4 0
2 years ago
Read 2 more answers
How to reduce into simpler terms.?
Sveta_85 [38]

Answer:

The simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

Step-by-step explanation:

Here are some simple observations regarding how to reduce a fraction into simpler terms:

  • A fraction is reduced to lowest or simplest terms by finding an equivalent fraction in which the numerator and denominator are as small as possible.
  • In order to reduce a fraction to lowest or simplest terms, divide the numerator and denominator by their (GCF). Note that (GCF) is also called Greatest Common Factor .

So, lets take a sample fraction and reduce into simpler terms.

Considering the fraction

\frac{45}{100}

\mathrm{Find\:a\:common\:factor\:of\:}45\mathrm{\:and\:}100\mathrm{\:in\:order\:to\:cancel\:it\:out}

\mathrm{Greatest\:Common\:Divisor\:of\:}45,\:100:\quad 5

\mathrm{Factor\:out\:}5\mathrm{\:from\:the\:numerator\:and\:the\:denominator}

45=5\cdot \:9\mathrm{,\:\quad }100=5\cdot \:20

so

\frac{45}{100}=\frac{5\cdot \:\:9}{5\cdot \:\:20}

\mathrm{Cancel\:the\:common\:factor:}\:5

     =\frac{9}{20}

Therefore, the simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

4 0
3 years ago
In the diagram below, m_MON = 1249, m _ MOP = 2x + 1, and m2 NOP = 2x
miv72 [106K]

Answer:

The answer is below

Step-by-step explanation:

The Angle Addition Postulate states that the measure of an angle formed by two or more angles which are placed side by side is the sum of the measures of the two angles.

Therefore:

∠MON = ∠MOP + ∠NOP (angle addition postulate)

Substituting values gives:

124 = (2x + 1) + (2x + 1)

124 = 2x + 2x + 1 + 1

124 = 4x + 2

subtracting 2 from both sides of the equation:

124 - 2 = 4x + 2 - 2

4x = 122

Dividing through by 4:

4x / 4 = 122 / 4

x = 30.5

Therefore ∠MOP = 2x + 1 = 2(30.5) + 1 = 62°, ∠NOP = 2x + 1 = 2(30.5) + 1 = 62°

∠MOP = 62°, ∠NOP = 62°

5 0
3 years ago
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